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stira [4]
3 years ago
15

Sodium Chloride (NaCl) has a molecular mass of 58 grams/mole. What is the molarity of a NaCl solution with a

Chemistry
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

2nd option

Explanation:

Molarity is the number of moles of the solute (NaCl) in 1 litre of the solution (NaCl solution).

Given: concentration= 232g/ L

what we are trying to achieve is __mol/ L.

So in 1 litre, we have 232g of NaCl.

To convert mass to mole, we divide it by the Mr.

Given that the Mr is 58g/mol,

number of moles

= 232 ÷58

= 4

Thus, 1 litre has 4 moles of NaCl.

Therefore, the molarity is 4.0 mol/L.

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The vapor pressure is obtained as 23.47 torr.

<h3>What is the vapor pressure?</h3>

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp =  vapor pressure lowering

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Number of moles of  glycerol =  32.5 g/92 g/mol = 0.35 moles

Number of moles  of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

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Δp =  0.012 * 23.76 torr

Δp =  0.285 torr

p1 = p° - Δp

p1 = 23.76 torr -  0.285 torr

p1 = 23.47 torr

Learn more about vapor pressure:brainly.com/question/14718830

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