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mixer [17]
4 years ago
9

A 50-N crate is pulled up a 5-m inclined plane by a worker at constant velocity. If the plane is inclined at an angle of 37° to

the horizontal and there exists a constant frictional force of 10 N between the crate and the surface, what is the force applied by the worker?

Physics
1 answer:
rodikova [14]4 years ago
8 0

Answer:F=40.09 N

Explanation:

Given

weight of crate W=50 N

Inclination \theta =37^{\circ}

Frictional Force f=10 N

as the crate is moving with constant velocity therefore net Force on crate is zero

F-50\sin (37)-f=0

F=50\sin (37)+10

F=30.09+10

F=40.09 N

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