A 50-N crate is pulled up a 5-m inclined plane by a worker at constant velocity. If the plane is inclined at an angle of 37° to
the horizontal and there exists a constant frictional force of 10 N between the crate and the surface, what is the force applied by the worker?
1 answer:
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<h2>Answer:</h2>
<em>Hello, </em>
<h3><u>Q</u><u>UESTION)</u></h3><em>✔ We have : a = v/Δt </em>
- a = 426/7
- a = 6 m/s²
The car's acceleration is therefore 6 m/s².
Answer:
31.55 m/s
Explanation:
Let the initial velocity of the arrow is u metre per second.
Angle of projection, θ = 40 degree
range = 100 m
Use the formula for the range.
100 = u^2 Sin(2 x 40) / 9.8
100 x 9.8 = u^2 Sin 80
u^2 = 995.11
u = 31.55 m/s
Answer:
Part a)
Part B)
Explanation:
As we know that when both the forces are acting on the object in same direction then we will have
as we know that
m = 10.6 kg
now we will have
Now two forces are in opposite direction then we have
Part A)
Now we will have from above two equation
Part B)
Similarly for other force we have