A 50-N crate is pulled up a 5-m inclined plane by a worker at constant velocity. If the plane is inclined at an angle of 37° to
the horizontal and there exists a constant frictional force of 10 N between the crate and the surface, what is the force applied by the worker?
1 answer:
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Answer:
Explanation:
Given that:
angular frequency = 11.3 rad/s
Spring constant (k) =
k = (11.3)² m
k = 127.7 m
where;
= 0.065 m
= 0.048 m
According to the conservation of energies;
∴