Whichh phrase best describes the function of cillia?

a wall of glass 2cm thickhas inside temperature of 30°C,outside temperature of15°C.how much heat is flowing through the glass(k=

kenny6666 [7]

Answer:46.5

Explanation:is the topical formula of F= 30x+15

5 0

4 years ago

What conversion takes place in a motor?

LenaWriter [7]

C should be the right answer! hopefully this helps!

4 0

3 years ago

A 28.0 kg child plays on a swing having support ropes that are 2.30 m long. A friend pulls her back until the ropes are 45.0 ∘ f

Dimas [21]

Answer

A)184.9J

B)=3.63m/s

C) Zero

Explanation:

A)potential energy of the child at the initial position, measured relative the her potential energy at the bottom of the motion, is

U=Mgh

Where m=28kg

g= 9.8m/s

h= difference in height between the initial position and the bottom position

We are told that the rope is L = 2.30 m long and inclined at 45.0° from the vertical

h=L-Lcos(x)= L(1-cosx)=2.30(1-cos45)

=0.674m

Her Potential Energy will now

= 28× 9.8×0.674

=184.9J

B)we can see that at the bottom of the motion, all the initial potential energy of the child has been converted into kinetic energy:

E= 0.5mv^2

where

m = 28.0 kg is the mass of the child

v is the speed of the child at the bottom position

Solving the equation for v, we find

V=√2k/m

V=√(2×184.9/28

=3.63m/s

C)we can find work done by the tension in the rope is given using expresion below

W= Tdcosx

where W= work done

T is the tension

d = displacement of the child

x= angle between the directions of T and d

In this situation, we have that the tension in the rope, T, is always perpendicular to the displacement of the child, d. x= 90∘ and cos90∘=0 hence, the work done is zero.

6 0

3 years ago

4. There are two categories of ultraviolet light. Ultraviolet A (UVA) has a wavelength ranging from 320 nm to 400 nm. It is not

vampirchik [111]

The ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Explanation:

The relationship between frequency and wavelength for an electromagnetic wave is the following:

$f = \frac{c}{\lambda}$

where

f is the frequency

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda$ is the wavelength

For the UVA, the range of wavelength is 320 nm - 400 nm, so

$\lambda_1 = 320 \cdot 10^{-9} m\\\lambda_2 = 400 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz\\f_2= \frac{3\cdot 10^8}{400\cdot 10^{-9}}=7.50\cdot 10^{14} Hz$

For the UVB, the range of wavelength is 280 nm - 320 nm, so

$\lambda_1 = 280 \cdot 10^{-9} m\\\lambda_2 = 320 \cdot 10^{-9} m$

So the corresponding frequencies are

$f_1 = \frac{3\cdot 10^8}{280\cdot 10^{-9}}=1.07\cdot 10^{15} Hz\\f_2= \frac{3\cdot 10^8}{320\cdot 10^{-9}}=9.38\cdot 10^{14} Hz$

So the ranges of frequency are:

UVA: $[7.50-9.38]\cdot 10^{14} Hz$

UVB: $[9.38-10.71]\cdot 10^{14} Hz$

Learn more about waves, frequency and wavelength:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0

3 years ago

If the frequency of the disorder in the population is 0.000081, what is the percentage of heterozygous carriers?

patriot [66]

The frequency of the disorder in the population is 0.000081, So, the percentage of heterozygous carriers would be 0.018.

Unlike homozygous, being heterozygous means you have two different alleles. You inherited a different version from each parent. In a heterozygous genotype, the dominant allele overrules the recessive one. Therefore, the dominant trait will be expressed. The recessive trait won't show, but you're still a carrier.

The presence of two different alleles at a particular gene locus. A heterozygous genotype may include one normal allele and one mutated allele or two different mutated alleles.

The Hardy-Weinberg equation is given by :

⇒ p² + 2pq + q² = 1

Here, p and q represent the individual allele frequencies.

Therefore, p² = frequency of homozygous condition represented by p.

q² = frequency of homozygous alleles represented by q.

and 2pq = frequency of heterozygous condition.

So, the correct answer is '2pq'.

⇒ (aa) q² = 0.000081,

⇒ (a) q = 0.009,

⇒ (A) p = 0.991,

⇒ (Aa) 2pq,

⇒ 0.018.

To learn more about heterozygous carriers here

brainly.com/question/17458395

#SPJ4

8 0

2 years ago