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3 years ago

What are the two methods fusion occurs within a star?

Physics

1 answer:

uranmaximum [27]3 years ago

6 0

Answer:

the proton-proton chain and the carbon-nitrogen-oxygen (CNO) cycle

Explanation:

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Si el sonido no atraviesa las paredes entonces, ¿por qué se escuchan las voces de los vendedores dentro de nuestra casa aún cuan

lutik1710 [3]

Answer:

DE HECHO EL SONIDO DÍ PUEDE ATRAVESAR LAS PAREDES, PERO

CUANDO ENTRA EN LA PARED, EL SONIDO VIAJA MÁS RÁPIDO QUE EN EL

AIRE Y CUANDO SALE DEL OTRO LADO, EL SONIDO VA A UNA

VELOCIDAD ALTA, POR ESTO LSA VOCES SE ESCUCHAN AUNQUE NO

MUY CLARAS.

Explanation:

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3 years ago

a uniform rod of length 1.5m is placed over a wedge at 0.5m from one end .a force of 100 N is applied at its one end near the we

andreev551 [17]

Explanation:

The rod is uniform, so the center of gravity is at the center, or 0.75 m from the end. The wedge is 0.5 m from the end, so the center is 0.25 m from the wedge.

Sum the torques about the wedge (it may help to draw a diagram first). Take counterclockwise to be positive.

∑τ = Iα

W (0.25 m) − (100 N) (0.50 m) = 0

W = 200 N

Sum the forces in the y direction.

∑F = ma

F − 100 N − 200 N = 0

F = 300 N

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4 years ago

Hopping is performed on 2 feet<br><br><br> True<br> False

gizmo_the_mogwai [7]

True welcome₩₩ sorry

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3 years ago

Read 2 more answers

How to add two on/off switches that can change the brightness of the light in circuit a without turning it off

Leokris [45]

Answer:

ressistor

Explanation:

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2 years ago

A soccer coach riding his bike reaches his office in xx hours. If he travels at 24 km/h, he reaches his office 5 minutes late. I

Elina [12.6K]

Answer:

18 km

Explanation:

Let 'd' be the distance between his house and office.

Normal time taken to reach the office = 'x' hours.

If speed is 24 km/h, time is increased by 5 minutes.

If speed is 30 km/h, time is reduced by 4 minutes.

We know that,

Time taken = Distance traveled ÷ Speed

So, when speed is 24 km/hr, time is increased by 5 minutes.

$1\ min = \frac{1}{60}\ h\\5\ min =\frac{5}{60}=\frac{1}{12}\ h$

So, time is $x+\frac{1}{12}$

Therefore,

$x+\frac{1}{12}=\frac{d}{24}\\\\x=\frac{d}{24}-\frac{1}{12}\\\\x=\frac{1}{12}(\frac{d}{2}-1)---------1$

Now, when speed is 30 km/h, time is reduced by 4 minutes or $\frac{4}{60}=\frac{1}{15}\ hours$

So, time now is $x-\frac{1}{15}$

Again using the time formula, we have

$x-\frac{1}{15}=\frac{d}{30}\\\\x=\frac{d}{30}+\frac{1}{15}\\\\x=\frac{1}{15}(\frac{d}{2}+1)-------------2$

Equations (1) and (2) are equal. So,

$\frac{1}{12}(\frac{d}{2}-1)=\frac{1}{15}(\frac{d}{2}+1)\\\\\frac{15}{12}(\frac{d}{2}-1)=\frac{d}{2}+1\\\\\frac{5d}{8}-\frac{5}{4}=\frac{d}{2}+1\\\\\frac{5d}{8}-\frac{d}{2}=1+\frac{5}{4}\\\\\frac{5d-4d}{8}=\frac{4+5}{4}\\\\\frac{d}{8}=\frac{9}{4}\\\\d=\frac{9\times 8}{4}=\frac{72}{4}=18\ km$

Therefore, the office is 18 km from his house.

6 0

3 years ago