(a) 0.249 (24.9 %)
The maximum efficiency of a heat engine is given by
where
Tc is the low-temperature reservoir
Th is the high-temperature reservoir
For the engine in this problem,
Therefore the maximum efficiency is
(b-c) 0.221 (22.1 %)
The second steam engine operates using the exhaust of the first. So we have:
is the high-temperature reservoir
is the low-temperature reservoir
If we apply again the formula of the efficiency
The maximum efficiency of the second engine is
Всяко действие има равно по големина и противоположно по посока противодействие.
Answer:
letter C. velocity hope this helps
Answer:
75.645 J
Explanation:
The kinetic energy is related to the mass and velocity by the formula ...
KE = 1/2mv²
For the given mass of 0.045 kg, and velocity of 41 m/s, the kinetic energy is ...
KE = 1/2(0.045 kg)(41 m/s)² = 75.645 J
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The unit of energy, joule, is a derived unit equal to 1 kg·m²/s².
