Answer:
Speed, u = 29.4 m/s
Explanation:
Given that, A ball thrown straight up climbs for 3.0 sec before falling, t = 3 s
Let u is speed with which the ball is thrown up. When the ball falls, v = 0
Using first equation of motion as :
v = u + at
Here, a = -g
So, u = g × t

u = 29.4 m/s
So, the speed with which the ball was thrown is 29.4 m/s. Hence, this is the required solution.
It’s North of the equator
<span>Correlations allow you to make inferences.</span>
Answer:F=648 N
Explanation:
Given
mass of man 
mass of Platform 
acceleration of system 
Let F be the force with which man pulls the rope which will also create a tension of F in rope
From Diagram





