Answer:
When the time of fall is doubled, the height of fall will be quadrupled
Explanation:
Given;
height of fall, h = d m
time of fall, t = t s
initial velocity of the object, u = 0 m/d
The height of fall of the object is calculated from the kinematic equation below;
where;
g is acceleration due to gravity, which is constant
if the time of fall is doubled, the height of fall is calculated as;
Therefore, when the time of fall is doubled, the height of fall will be quadrupled
The question is incomplete, the complete question is
When an RL circuit is connected to a battery, what happens to the potential difference across the resistor and the emf across the inductor?
The resistor potential is constant and the inductor emf increases.
The resistor potential is constant and the inductor emf decreases.
The resistor potential is constant and the inductor emf is constant.
The resistor potential decreases and the inductor emf is constant.
The resistor potential decreases and the inductor emf increases.
The resistor potential decreases and the inductor emf decreases.
The resistor potential increases and the inductor emf increases.
The resistor potential increases and the inductor emf is constant.
The resistor potential increases and the inductor emf decreases.
Answer:
The resistor potential increases and the inductor emf decreases.
Explanation:
From Kirchoff's rule, we can easily see that voltage across the inductor decreases steadily in a RL circuit until it finally gets to zero when the circuit is connected to a battery. A graph of the drop in potential across the inductor is attached for more clarity.
The drop shown in figure (b) in the image attached is the drop in potential across the inductor when an RL circuit is connected to a battery.
Answer:
15000N/m²
Explanation:
Given parameters:
Weight = 450N
Total area = 0.03m²
Unknown:
Pressure under her feet = ?
Solution:
Pressure is the force per unit area on a body.
Pressure =
Weight is a type of force;
Pressure = = 15000N/m²
Answer:
the required minimum magnitude of the force F is 21 N
Explanation:
Given the data in the question,
m = 5 kg
width = 60 cm
height = 80 cm
Let force is F represent in the image below,
so when the block about to rotate normal shifted to edge of cube
mg(w/2) = Fh
F = mg(w/2) / h
we know that g = 9.8 m/s²
we substitute
F = (5 × 9.8 ( 60/2)) / 70
F = (5 × 9.8 × 30 ) / 70
F = 1470 / 70
F = 21 N
Therefore, the required minimum magnitude of the force F is 21 N
