Answer:
Velocity of skater after throwing the snowball is 2.57 m/s
Explanation:
Given :
Mass of skater, M = 62.2 kg
Mass of snowball, m = 0.145 kg
Velocity of snowball relative to ground, v = 39.3 m/s
Consider v₁ be the velocity of skater after throwing the snowball.
According to the problem, initially the velocity of skater and snowball is same. So,
Velocity of skater before throwing snowball, u = 2.66 m/s
Applying conservation of momentum,
Momentum before throwing snowball = Momentum after throwing snowball
(M + m) u = Mv₁ + mv
Substitute the suitable values in the above equation.
v₁ = 2.57 m/s
E. i - Energy (w) = Power x Time
Energy = 40 x 3600
= 14,400 joules
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Answer
The answer and procedures of the exercise are attached in the following archives.
Step-by-step explanation:
You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.
The spring constant is 66.7 N/m
Explanation:
First of all, we have to find the magnitude of the force acting on the spring. This is equal to the weight of the mass hanging on the spring, which is:
where:
m = 0.50 kg is the mass of the object
is the acceleration of gravity
Substituting,
Now we can use Hookes' law to find the constant of the spring:
where
F is the force applied
k is the spring constant
x is the stretching of the spring
Here we have:
F = 5 N
While the stretching is
x = 0.075 m
Therefore, ignoring the negative sign in the formula (which only tells us the direction), we find the spring constant:
#LearnwithBrainly
Answer:
C
Explanation:
I think it could be C because, gasoline which is used by cars is a big factor in more emission being placed in the air. With electrical powered cars like Tesla, emission can decrease.
Sorry if i'm wrong
But, hope this helps :)