B is the answer because the area between the velocity time graph and the x-axis is the distance traveled. If you look at the velocity time graph from 0-2, seconds you will see an area of 40m. Only choice B matches that at 2 seconds, the distance traveled is 40m. You can go on to confirm the remaining trip matches that of B by calculating the 2-4 seconds of the velocity time graph area between the x-axis and graph as -40m (negative because area is under the x-axis). Again, it matches graph B, showing that the total distance traveled is 0 for the entire trip.
Answer:
There's a video called Drawing Position vs Time Graphs made by MrDGenova that may help you, it's only three minutes long.
Explanation:
Hope that helps, if not, you could tell me what you don't understand and I could try explaining it in further detail.
Answer:
I think is o or mavey it could be D
The concept required to solve this problem is hydrostatic pressure. From the theory and assuming that the density of water on that planet is equal to that of the earth we can mathematically define the pressure as
Where,
= Density
h = Height
g = Gravitational acceleration
Rearranging the equation based on gravity
The mathematical problem gives us values such as:
Replacing we have,
Therefore the gravitational acceleration on the planet's surface is
The strength of the electric field is 1.035 * 10^7 N/C.
<h3>What is the electric field?</h3>
The term electric field refers to the region in space where the influence of a charge is felt. Now we know that the electric field is obtained form the formula;
E = F/q
E = electric field
F = electric force
q = magnitude of charge
F = 8.8 * 10^-3 * 10 m/s^2 = 0.088 N
q = -8.5 nc or -8.5 * 10^-9 C
E = 0.088 N/ -8.5 * 10^-9 C
E = 1.035 * 10^7 N/C
Learn more about electric field:brainly.com/question/15800304
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