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gizmo_the_mogwai [7]
3 years ago
15

Please help!!!!!!!!

Physics
1 answer:
Setler [38]3 years ago
8 0

Answer:

Option C. 83.8 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of object = 2 Kg

Velocity (v) of the object = 5 m/s

Height (h) = 3 m

Mechanical energy =.?

Next, we shall determine the kinetic energy of the object. This can be obtained as shown below:

Mass (m) of object = 2 Kg

Velocity (v) of the object = 5 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 2 × 5²

KE = 1 × 25

KE = 25 J

Next, we shall determine the potential energy of the object. This can be obtained as shown below:

Mass (m) of object = 2 Kg

Height (h) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Potential energy (PE) =.?

PE = mgh

PE = 2 × 9.8 × 3

PE = 58.8 J

Finally, we shall determine the mechanical energy of the object. This can be obtained as shown below:

Kinetic energy (KE) = 25 J

Potential energy (PE) = 58.8 J

Mechanical energy =?

Mechanical energy = KE + PE

Mechanical energy = 25 + 58.8

Mechanical energy = 83.8 J

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#1

\\ \rm\dashrightarrow P=VI\implies V=\dfrac{P}{I}

\\ \rm\dashrightarrow V=\dfrac{0.4\times 10^3}{33\times 10^{-3}}

\\ \rm\dashrightarrow V=0.012\times 10^{-6}

\\ \rm\dashrightarrow V=12mV

#2

\\ \rm\dashrightarrow R=\rho \dfrac{\ell}{A}

\\ \rm\dashrightarrow \rho =\dfrac{RA}{\ell}

\\ \rm\dashrightarrow \rho=\dfrac{86.3(0.4\times 10^6)}{69}

\\ \rm\dashrightarrow \rho=0.5\times 10^{6}

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#3

Ohms law

\\ \rm\dashrightarrow R=\dfrac{V}{I}

\\ \rm\dashrightarrow R=\dfrac{7(10^3)}{6(10^{-6})}

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