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3 years ago

Please help!!!!!!!!

Physics

1 answer:

Setler [38]3 years ago

8 0

Answer:

Option C. 83.8 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) of object = 2 Kg

Velocity (v) of the object = 5 m/s

Height (h) = 3 m

Mechanical energy =.?

Next, we shall determine the kinetic energy of the object. This can be obtained as shown below:

Mass (m) of object = 2 Kg

Velocity (v) of the object = 5 m/s

Kinetic energy (KE) =?

KE = ½mv²

KE = ½ × 2 × 5²

KE = 1 × 25

KE = 25 J

Next, we shall determine the potential energy of the object. This can be obtained as shown below:

Mass (m) of object = 2 Kg

Height (h) = 3 m

Acceleration due to gravity (g) = 9.8 m/s²

Potential energy (PE) =.?

PE = mgh

PE = 2 × 9.8 × 3

PE = 58.8 J

Finally, we shall determine the mechanical energy of the object. This can be obtained as shown below:

Kinetic energy (KE) = 25 J

Potential energy (PE) = 58.8 J

Mechanical energy =?

Mechanical energy = KE + PE

Mechanical energy = 25 + 58.8

Mechanical energy = 83.8 J

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A 45.2-kg person is on a barrel ride at an amusement park. She stands on a platform with her back to the barrel wall. The 3.74-m

elena-14-01-66 [18.8K]

Answer:

1,230N

Explanation:

1. Name of the variables:

$f:frequency\\\\ \omega:angular\text{ }speed\\\\ a_c:centripetal\text{ }acceleration\\\\ F_c:centripetal\text{ }force\\ \\ m:mass\\ \\ d:diameter\\ \\ r:radius\\ \\ g:gravitational\text{ }acceleration$

2. Formulae:

$f=\dfrac{number\text{ }of\text{ }revolutions}{time}$

$\omega=2\pi f$

$a_c=\omega^2 r$

$F_c=m\times a_c$

3. Solution (calculations)

$f=\dfrac{1}{1.65s}=0.\overline{60}s^{-1}$

$\omega=2\pi\times0.\overline{60}\approx 3.808rad/s$

$a_c=(3.808rad/s)^2\times (3.74/2m)=27.12m/s^2$

$F_c=45.2kg\times27.12m/s^2=1,225.67N\approx 1,230N$

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3 years ago

Which quantity measures the maximum distance an object on a spring moves from the equilibrium position during oscillation?

nasty-shy [4]

The appropriate response is amplitude. A measure of its change over a solitary period. There are different meanings of plentifulness, which are all elements of the extent of the distinction between the variable's outrageous qualities. In more seasoned writings, the stage is now and again called the adequacy.

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3 years ago

Read 2 more answers

Consider a railroad bridge over a highway. A train passing over the bridge dislodges a loose bolt from the bridge, which proceed

photoshop1234 [79]

Answer:

The railroad tracks are 13 m above the windshield (12 m without intermediate rounding).

Explanation:

First, let´s calculate the time it took the driver to travel the 27 m to the point of impact.

The equation for the position of the car is:

x = v · t

Where

x = position at time t

v = velocity

t = time

x = v · t

27 m = 17 m/s · t

27 m / 17 m/s = t

t = 1.6 s

Now let´s calculate the distance traveled by the bolt in that time. Let´s place the origin of the frame of reference at the height of the windshield:

The position of the bolt will be:

y = y0 + 1/2 · g · t²

Where

y = height of the bolt at time t

y0 = initial height of the bolt

g = acceleration due to gravity

t = time

Since the origin of the frame of reference is located at the windshield, at time 1.6 s the height of the bolt will be 0 m (impact on the windshield). Then, we can calculate the initial height of the bolt which is the height of the railroad tracks above the windshield:

y = y0 + 1/2 · g · t²

0 = y0 -1/2 · 9.8 m/s² · (1.6 s)²

y0 = 13 m

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3 years ago

g A 475-gram ball is traveling horizontally at 12.0 m/s to the left when it is suddenly struck horizontally by a bat, causing it

AlexFokin [52]

Answer:

7.64 ms

Explanation:

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3 years ago

g a mass of 1.3 kg is pushed horizontally against a massless spring with a spring constant of 58 n/m until the spring compresses

ExtremeBDS [4]

Answer: $1.102\ J$

Explanation:

Given

Mass $m=1.3\ kg$

Spring constant $k=58\ N/m$

Compression in the spring $x=19.5\ cm\ or\ 0.195\ m$

When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.

$\Rightarrow \dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}\cdot 58\cdot (0.195)^2=\dfrac{1}{2}mv^2\\\\\Rightarrow \dfrac{1}{2}mv^2=1.102\ J$

The kinetic energy of the mass is 1.102 J.

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3 years ago