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Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set in

Yuki888 [10]

Answer:

0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

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For d = 0.20 meters, the period is ...

T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

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<em>Additional comment</em>

The formula for the oscillator period is usually seen as ...

T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

k = mg/d

Using that in the formula, we find it simplifies to ...

$T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}$

5 0

2 years ago

What is convection ?

bagirrra123 [75]

Convection is the rise of hot air and the drop of cold air due to a large amount of molecules being moved usually in gas form.\

Hope this helps!

5 0

4 years ago

Read 2 more answers

A 10 kg object moving to the left collides with and sticks to a 3 kg object moving to the right. Which of the following is true

valina [46]

Answer:

"Cannot be determined," if that's an answer choice. It depends on the velocities of both objects, since momentum=mass*velocity.

Explanation:

8 0

3 years ago

A person driving her car at 43 km/h approaches an intersection just as the traffic light turns yellow. She knows that the yellow

siniylev [52]

Answer:

If she hits the brakes, she will travel 13m before stopping. If she hits the gas, she will travel 28 before the light turns red. She should try to stop

Explanation:

To know how far she will travel before stopping, we need to use a kinematic formula which initial final velocity (Vf), initial velocity (V0), acceleration (a) and distance traveled(x):

$V_{f}^{2}=V_{0} ^{2} +2ax$

The moment in which she stops is when the final velocity equals zero. In this case, initial velocity is 43km/h=12m/s, and its maximum deceleration is -5.4m/s^2. Plugging in these values and solving for x:

$0^2=(12m/s)^2+2(-5.4m/s)x\\x=13m$