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frosja888 [35]
3 years ago
9

Solve the following problem. Round answer to two decimal places when necessary.

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

Answer:

D = 11

Step-by-step explanation:

A = 4

B = 9

C = 11

D = 4 + (2 * 9) - 11

D = 4 + 18 - 11

D = 22 - 11

D = 11

brainliest plz

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To win a particular lottery game, it is necessary to match numbers on 5 balls that are randomly picked from 65 balls numbered 1-
emmainna [20.7K]

Answer: 5.34*10^{-5}

Step-by-step explanation:

given data:

number of balls = 65.

special black ball that is picked from 10 other balls = numbered 0-9.

<u><em>Solution:</em></u>

<em>probability that a single lottery ticket will match 2 balls and the special black ball.</em>

= 65C2*9C1\\\\= 18720\\\\=\frac{1}{18720} \\\\= 5.34*10^{-5}

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3 years ago
Express the recurring decimal 0.142 recurring as a fraction in its simplest form.
kupik [55]

Answer:

7/165

Step-by-step explanation:

We take number after the decimal point     042

then we subtract  the non repeating.In this case is 0 so we not subtract anything

This will be the numerator  42

For each repeating decimal we write a 9 (in this case 2 nines)

For each non repeating decimal we write a zero

Denominator is 990

42/990  =  7/165

7:165 = 0.0424242

I think this is what you do. Hope it helps!

5 0
3 years ago
The map shows the location of the airport and a warehouse in a city. Though not displayed on the map, there is also a factory 72
lisov135 [29]
\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\sqrt{(-27-27)^2+(36+36)^2}\\\\ \sqrt{54^2+72^2} \\\\ \sqrt{8100} \\\\90\\\\\\90+54 =\boxed { 144}\\\\\sf The~ distance~ 90~ is~ from ~the~ warehouse~ to ~the ~airport\\\\The~ distance~ 54~ is~ from ~the~ airport~ to ~the~ factory\\\\So,~ the~ total~ distance~ is~ 144
6 0
3 years ago
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Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I
sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)

Back from the store:

s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles

∴ length of trip to the store = t₁

from eqn (1)

t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours

7 0
3 years ago
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