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3 years ago

Silver chloride was reacted with magnesium hydroxide, in which magnesium displaced silver

Chemistry

1 answer:

Elza [17]3 years ago

8 0

Answer:

<h3>The precipitate is MgCl2</h3>

Explanation:

The reaction that is described goes as follows:

2AgCl + Mg(OH)2 ---> MgCl2 + 2AgOH

The precipitate here is the MgCl2 salt.

I hope it helped!

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likoan [24]

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At anode 2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$

At Cathode: 2 $H^{+}$ + $2e^{-}$ ==> H₂

Since the question states that you are using an aqueous solution of MnCl₂, so ions will have present are, H₂O, $H^{+}$ , $Mn^{2+}$ and $Cl^{-}$

Now at Anode reaction will occur as given:

2 $Cl^{-}$ ==> Cl₂+ $2e^{-}$ + H₂O ==> $ClO^{-}$ + 2 $H^{+}$ + $Cl^{-}$ (will occur)

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2 $H^{+}$ + $2e^{-}$ ==> H₂ (will occur)

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The reduction potentials for $H^{+}$ is zero whereas reduction potential for $Mn^{2+}$ is - 1.18V.

The reduction potential of a species is its tendency to gain electrons and get reduced. It is measured in millivolts or volts. Larger positive values of reduction potential are indicative of a greater tendency to get reduced.

To learn more about the half reaction please click on the link brainly.com/question/13186640

#SPJ4

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