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cricket20 [7]
3 years ago
12

What is the LD50 of a substance?

Chemistry
1 answer:
creativ13 [48]3 years ago
8 0

<em>In toxicology, the median lethal dose, LD₅₀, LC₅₀ or LCt₅₀ is a measure of the lethal dose of a toxin, radiation, or pathogen. The value of LD₅₀ for a substance is the dose required to kill half the members of a tested population after a specified test duration.</em>

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When water droplets in a cloud combine, become too heavy, and fall to the ground as rain, snow, sleet, or hail, we are experienc
tatiyna

Answer:

precipitation

Explanation:

7 0
3 years ago
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Adding 5.25 g of to 130 g of water in a coffee-cup calorimeter (with stirring to dissolve the salt) resulted in a decrease in te
xxTIMURxx [149]

Answer:

ΔHrxn =  - 1534.3 J

Explanation:

Given the assumptions and the formula for the change in enthalpy:

ΔHrxn = m x C x ΔT,  where

               m is the mass of solution given 135.4 g

               C is the heat capacity 4.2 J/g .K  and,

               ΔT is the change in temperature

we have ,

T₁ = ( 18.1 + 273) K = 291.1 K

T₂ = ( 15.4 +273) K = 288.4 K

ΔHrxn =  135.3 g x 4.2 J/gK x ( 288.4 -291.1 ) K = - 1534.3 J

After verifying our result has the correct unit, the answer is -1534.3 Joules, and the negative sign tells us it is an endothermic reaction decreasing the final temperature.

4 0
3 years ago
Does bacteria need water to live
Aleks [24]
No. bacteria only needs food to live along with other special needs depending on the type of bacteria
6 0
4 years ago
1. write the formula for the following ionic compound: Calcium Carbonate
Salsk061 [2.6K]

Answer:

CaCO3

Explanation:

The molecule is formed by the calcium cation Ca+2 and the carbonate anion CO3−2.

3 0
2 years ago
How many moles of ScCl3 can be produced when 10.00 mol Sc react with 9.00 mol Cl2
Nuetrik [128]

Answer:

Moles of ScCl_3 = 6 moles

Explanation:

The reaction of Sc and Cl_2 to make ScCl_3 is:

2Sc+3Cl_2⇒2ScCl_3

The above reaction shows that 2 moles of Sc  can react with 3 moles of Cl_2 to form ScCl_3.

Mole Ratio= 2:3

For 10 moles of Sc we need:

Moles of Cl_2 = Moles of Sc *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 = 10 *\frac{3 moles of Cl_2}{2 Moles of Sc}

Moles of Cl_2 =15 moles

So 15 moles of Cl_2 are required to react with 10 moles of Sc but we have 9 moles of Cl_2 , it means Cl_2 is limiting reactant.

Moles of ScCl_3=Given\  Moles\  of\ Cl_2 *\frac{2\  Moles\ o\ fScCl_3}{3\ Moles\ of\ Cl_2}

Moles\ of\  ScCl_3=9 *\frac{2\  Moles\ of\ ScCl_3}{3\ Moles\ of\ Cl_2}

Moles of ScCl_3= 6 moles

4 0
3 years ago
Read 2 more answers
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