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cricket20 [7]
3 years ago
14

Can someone help me on this​

Mathematics
1 answer:
klio [65]3 years ago
8 0

Answer:

A. The balloon rises 1 mile every 1/5 minute.

Step-by-step explanation:

1. Height = 1/5Time

2. For every mile risen, it takes 1/5 Minutes.

or if its easier to understand the other way around

For every 1/5 minutes, the balloon rises 1 mile

I hope my answer is correct and that you get a good grade!

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Find the inverse function
Troyanec [42]

The inverse of the function is f(x) = x^{3} + 8

In order to find the inverse of any function, start by switching the f(x) and x. Then solve for the new f(x). The result will be the inverse function. The work is below for you.

f(x) = \sqrt[3]{x - 8} ----> Switch f(x) and x

x = \sqrt[3]{f(x) - 8} ----> Cube both sides

x^{3} = f(x) - 8 ----> Add 8 to both sides

f(x) = x^{3} + 8

4 0
3 years ago
Which series of transformations will not map figure H onto itself
7nadin3 [17]

Answer:

D

Step-by-step explanation:

Given a square with vertices at points (2,1), (1,2), (2,3) and (3,2).

Consider option A.

1st transformation (x+0,y-2) will map vertices of the square into points

  • (2,1)\rightarrow (2,-1);
  • (1,2)\rightarrow (1,0);
  • (2,3)\rightarrow (2,1);
  • (3,2)\rightarrow (3,0).

2nd transformation = reflection over y = 1 has the rule (x,2-y). So,

  • (2,-1)\rightarrow (2,3);
  • (1,0)\rightarrow (1,2);
  • (2,1)\rightarrow (2,1);
  • (3,0)\rightarrow (3,2)

These points are exactly the vertices of the initial square.

Consider option B.

1st transformation (x+2,y-0) will map vertices of the square into points

  • (2,1)\rightarrow (4,1);
  • (1,2)\rightarrow (3,2);
  • (2,3)\rightarrow (4,3);
  • (3,2)\rightarrow (5,2).

2nd transformation = reflection over x = 3 has the rule (6-x,y). So,

  • (4,1)\rightarrow (2,1);
  • (3,2)\rightarrow (3,2);
  • (4,3)\rightarrow (2,3);
  • (5,2)\rightarrow (1,2)

These points are exactly the vertices of the initial square.

Consider option C.

1st transformation (x+3,y+3) will map vertices of the square into points

  • (2,1)\rightarrow (5,4);
  • (1,2)\rightarrow (4,5);
  • (2,3)\rightarrow (5,6);
  • (3,2)\rightarrow (6,5).

2nd transformation = reflection over y = -x + 7 will map vertices into points

  • (5,4)\rightarrow (3,2);
  • (4,5)\rightarrow (2,3);
  • (5,6)\rightarrow (1,2);
  • (6,5)\rightarrow (2,1)

These points are exactly the vertices of the initial square.

Consider option D.

1st transformation (x-3,y-3) will map vertices of the square into points

  • (2,1)\rightarrow (-1,-2);
  • (1,2)\rightarrow (-2,-1);
  • (2,3)\rightarrow (-1,0);
  • (3,2)\rightarrow (0,-1).

2nd transformation = reflection over y = -x + 2 will map vertices into points

  • (-1,-2)\rightarrow (4,3);
  • (-2,-1)\rightarrow (3,4);
  • (-1,0)\rightarrow (2,3);
  • (0,-1)\rightarrow (3,2)

These points are not the vertices of the initial square.

5 0
3 years ago
PLEASE HELP!!!!! I WILL MARK BRAINLIEST AND RATE 5 STARS!!
dedylja [7]

Answer:

37°

Step-by-step explanation:

sum of exterior angles of a polygon is 360°

so, 41+(x+13)+(2x-14)+(3x-22)+(x-3)+38+(x+11)=360

8x+64=360, subtract 64 from both sides

8x=296

x=37°

6 0
2 years ago
Four consecutive odd integers add up to -48. What is the least of these integers?
Semmy [17]

Answer:

-9

Step-by-step explanation:

Four consecutive odd integers be (2x - 3),(2x -1),(2x + 1),(2x + 3)

2x-3 + 2x - 1 +2x+1 + 2x+3 = -48

2x + 2x + 2x +2x - 3 - 1 + 3 + 1 = -48

8x = -48

x = -48/8

x = -6

Least of these integer = 2x + 3 = 2*(-6) + 3 = -12 + 3 = -9

3 0
3 years ago
|2s|+19=13<br> Help me please
Mnenie [13.5K]

 \textsf{Hey there!}

\mathsf{|2s| + 19= 13}\\\textsf{Solve both sides by -19}\\\mathsf{|2s|+19+ (-19)=13+(-19)}\\\mathsf{Cancel\ out:\ 19 + (-19) \  because\ that\ gives\ you\ 0}\\\mathsf{Keep: 13 + (-19)\ because\ that\  helps\ us\ solve\ for\ our\ answer}\\\mathsf{13 + (-19) = -6}\\\mathsf{Solve\ for\ absolute\ value: |2s| = -6}\\\mathsf{Any\ absolute\ values\ CANNOT\ be\ less\ than\ 0}\\\mathsf{\boxed{\boxed{\mathsf{Thus, \ this\ make\ your\ answer\ is: \boxed{\boxed{\bf{No\ solution}}}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

4 0
3 years ago
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