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Furkat [3]
3 years ago
8

What is the volume of the cuboid if it is 0.4cm x 1.5cm x 3.25cm

Mathematics
1 answer:
N76 [4]3 years ago
8 0
Find the volume with the equation

v = length × width × height

For your cuboid

v = .4cm×1.5cm×3.25cm
v = 1.95 cm^3

Don't forget to always put your units!
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Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
If B is the midpoint of line AC, AC = CD, AB = 3x+4, AC=11x-17, and CE = 49, find DE. (Show work)
larisa [96]

Answer:

2(3x+4) = 11x-17

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Let me know if this helps!

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try this for answer (11×3.5)-9=x

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Answer:

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Step-by-step explanation:

this would be 13

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