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Tamiku [17]
2 years ago
12

Find the perimeter of quadrilateral ABCD. Round to the nearest tenth.

Mathematics
1 answer:
Olegator [25]2 years ago
4 0

Answer:

14.6 units

Step-by-step explanation:

AB = \sqrt{(1-3)^2+(3-5)^2}

AB =\sqrt{8}

BC = \sqrt{(3-1)^2+(-1-3)^2}=\sqrt{20}

CD = \sqrt{(5-3)^2+(3-(-1))} = \sqrt{20}

DA = \sqrt{(5-3)^2+(3-5)^2} = \sqrt{8}

Primeter = \sqrt{8} + \sqrt{20} + \sqrt{20} +\sqrt{8} = 14.6

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