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Mama L [17]
3 years ago
13

Determjne the density of liquid whose relative density is 1.25 given that the density is 1000kgm-3​

Physics
1 answer:
IgorC [24]3 years ago
7 0

Answer:

divide the density of solution by density of water

EXPLANATION:

LIKE:

1.25÷1000kgm-3

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The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent ho
faltersainse [42]

Answer:

Explanation:

Let mass of cylinder be M

Moment of inertia of cylinder

= 1/2 M R² r is radius of cylinder

If radius of equivalent  hoop be k

Mk² = 1/2 x MR²

k = R / √2

1.2 / 1.414

Radius of gyration = 0.848 m

b )

moment of inertia of spherical shell

= 2 / 3 M R²

Moment of inertia of equivalent hoop

Mk²

So

Mk² = 2 / 3 M R²

k = √2/3 x R

= .816 X 1.2

Radius of gyration = .98 m

c )

Moment of inertia of solid sphere

= 2/5 M R²

Moment of inertia of equivalent hoop

= Mk²

Mk² = 2/5 M R²

k √ 2/5 R

Radius of gyration = .63 R

6 0
4 years ago
An isotope of an element will be radioactive if it has an unstable ratio of____and_____
sammy [17]
Neutrons and protons
5 0
4 years ago
. Potential energy is a vector quantity True or false?
DedPeter [7]
False. Energy in any form is a scalar quantity. 
6 0
3 years ago
A pulley system has an efficiency of 87.5 percent.
Gelneren [198K]

Answer:

work done on desk = m g h = 105 * 9.81 * 2.46 = 2534 Joules

Explanation:

so work in = 2534 / 0.875 = 2896 Joules

that is your 648 times distance your hand moved holding the rope

2896 = 648 * x

4.47 meters

I think maybe a typo, 648 N is too big, maybe 64.8 ? Any block and tackle system does better than that.

7 0
3 years ago
Problem: Hooke's law states that the force on a spring varies directly with the distance that it is stretched. If a spring has a
Scorpion4ik [409]

Answer:

Restoring force of the spring is 50 N.

Explanation:

Given that,

Spring constant of the spring, k = 100 N/m

Stretching in the spring, x = 0.5 m

We need to find the restoring force of the spring. It can be calculated using Hooke's law as "the force on a spring varies directly with the distance that it is stretched".

F=kx

F=100\ N/m\times 0.5\ m

F = 50 N

So, the restoring force of the spring is 50 N. Hence, this is the required solution.

7 0
4 years ago
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