Whats the value of b ?

Texas chic. Next question

Maksim231197 [3]

When u have an outlier, u want to use the median.....in this case, the median is 4

4 0

3 years ago

20 is what percent of 52

Maslowich

The process here is finding out the smallest number's % towards the largest number.

Divide 20 by 52:
20/52 = 0.38 (estimated) | This is the % in decimal form, which is 38%.

Conclusion: 20 is 38% of 52.

{---Further Elaboration for Future Reference---}

Finding the Smallest Number:

What number is 25% of 60?

Multiply 60 by the decimal form of 25%.
60 * 0.25 = 15 | 15 is 25% of 60.

Finding the Percentage. (Like what we already did.)

30 is what percent of 150?

Divide 30 by 150.
30/150 = 0.2 | 30 is 20% of 150.

Finding the Largest Number.

12 is 30% of what number?

Divide 12 by the decimal form of 30%.
12/0.3 = 40 | 12 is 30% of 40.

I hope this helps, have a great rest of your day! ^ ^
| | Ghostgate | |

5 0

3 years ago

Read 2 more answers

What is the solution of the equation?<br>-5=q+2

jeyben [28]

Step-by-step explanation:

-5=q+2

-5+2=q

q= -3

hope it helps.

3 0

3 years ago

Read 2 more answers

The number of events is 29, the number of trials is 298, the claimed population proportion is 0.10, and the significance leve

Nina [5.8K]

Answer:

$z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155$

$p_v =2*P(Z$

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

$\hat p=\frac{29}{298}=0.0973$ estimated proportion

$p_o=0.1$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:

Null hypothesis: $p=0.1$

Alternative hypothesis: $p \neq 0.1$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

7 0

2 years ago

The attendant at a parking lot compared the number of hybrid vehicles to the total number of vehicles in the lot over a weekend.

EastWind [94]

We are given:

The ratios of the number of hybrid vehicles to the total number of vehicles in the lot over a weekend (3 days) are equivalent.

This means that if on day 1, 100 hybrid cars parked and there are 300 cars in total, the ratio is 1 is to 3.

Therefore, on day 2 and 3, we can determine the number of hybrid cars parked given the total number of cars parked using the ratio, and vice versa.

3 0

3 years ago