Answer: Frequency of dominant allele is 0.9 and people who are heterozygous for the condition are 648.
Explanation:
According to Hardy-Weinberg equation, p represents frequency of dominant allele, q represent frequency of recessive allele.
And also p + q = 1.
Given frequency of recessive allele, q as 0.1.
p, frequency of dominant allele is
1 - 0.1 = 0.9
Therefore, frequency of dominant allele= 0.9.
Number of people that will be heterozygous will gotten from the percentage of heterozygous of the total population.
Heterozygous is represented as 2pq, that is the product of 2,p and q.
Therefore we have 2 multiply by p by q.
2 x 0.9 x 0.1= 0.18 or 18%.
Since we are to find the number and not only percentage:
So from the population given as 3600, number of heterozygous is 18% of 3600.
18% of 3600 = 648.
