In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many
1 answer:
There are 2 lone pairs
<h3>Further explanation </h3>Given
a molecule of calcium sulfide
two valence electron of Calcium(Ca)
six valence electrons of Sulfur(S)
Required
number of lone pairs of electrons
Solution
Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound
Valence electrons are electrons used in a chemical bond
To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,
A lone pair electrons means refers to an unshared pair of electrons(not bonding to the other atoms)
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Answer: P= 1.64 atm
Explanation: solution attached.
Use Ideal gas law
PV= nRT
Derive for P
P= nRT/V R= 0.08205 L.atm/mol.K
Substitute the values.
Based on the calculations, the approximate ductility (%el) of this brass is equal to 2.3%.
<u>Given the following data:</u>
- Yield strength = 230 mpa (33360 psi).
Ductility can be defined as an important property of a material which determines its ability to become elongated due to the application of stress.
Mathematically, the ductility of a material can be expressed as percentage elongation in length:
<u>Where:</u>
is the original length.
is the final length.
is the yield strength.
For this exercise, let us assume the original length of this brass is equal to 100 meters.
Substituting the parameters into the formula, we have;
Ductility = 2.3%.
Read more on ductility here: brainly.com/question/828860