Answer:
0.02moles
Explanation:
To answer this question, the general gas law equation is used. The General gas law is:
Pv = nRT
Where; P = standard atmospheric pressure (1 atm)
V = volume (L)
n = number of moles
R = Gas law constant
T = Temperature
For this question; volume = 1.00L, atmospheric pressure (P) = 1 atm, R = 0.0821 L-atm / mol K, T = 600K, n = ?
Therefore; Pv = nRT
n = PV/RT
n = 1 × 1/ 0.0821 × 600
n = 1/49.26
n = 0.0203moles
Hence, there are 0.02 moles of gas.
Answer: 5.43x10^23 g/mole M&M's
Explanation:
1 bag of M&M's = 1.75oz (1.75oz)*(453.6g/16oz) = 49.61 g
1 bag = 55 M&M's
(49.61 g)/55 M&M = 0.9021 g/MM
1 mole M&M's = 6.023x10^23 M&M's
(6.023x10^23 M&M's)*(0.9021 g/MM's) = 5.43x10^23 g/mole molar mass
This was a riddle that has been included in a chemistry test.
The answer was a combination of letters that served as answers to previous questions.
How many varmints does it take to ruin a chemist's lawn? MOLES
Hopefully this helps sorry