In a molecule of calcium sulfide, calcium has two valence electron bonds, and a sulfur atom has six valence electrons. How many
1 answer:
There are 2 lone pairs
<h3>Further explanation </h3>Given
a molecule of calcium sulfide
two valence electron of Calcium(Ca)
six valence electrons of Sulfur(S)
Required
number of lone pairs of electrons
Solution
Lewis structure shows the form of bonds that occur in the valence electrons of an element or compound
Valence electrons are electrons used in a chemical bond
To achieve stability, the element S needs 2 more electrons which are obtained from 2 electrons from the Ca element,
A lone pair electrons means refers to an unshared pair of electrons(not bonding to the other atoms)
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Answer: The velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.
Explanation:
Given: = 0.2 kg,
= 0.15 kg
= 2 m/s,
= 0 m/s,
= ?,
= 1.5 m/s
Formula used is as follows.
where,
v = velocity before collision
v' = velocity after collision
Substitute the values into above formula as follows.
Thus, we can conclude that the velocity of the first ball is 0.875 m/s if the second ball travels at 1.5 m/s after collision.