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3 years ago

According to the following reaction, how many grams of water are produced in the complete reaction of grams of sulfuric acid?

Chemistry

1 answer:

Natasha2012 [34]3 years ago

5 0

This question requires the mass of sulfuric acid and a balance equation. The complete question is given below

Question:

According to the following reaction, how many grams of water are produced in the complete reaction of 24.1 grams of sulfuric acid?

H₂SO₄(aq) + Zn(OH)₂(s) ---------> ZnSO₄(aq) + 2H₂O(l)

Answer:

8.85 grams of water is obtained from 24.1 grams of sulfuric acid according to the given reaction

Explanation:

In this problem, the mass of water can be determined by using the balanced chemical equation.

Step 1: Write all data

Molar mass of water = 18 g

Molar mass of sulfuric acid = 98 g

Given mass of sulfuric acid = 24.1 g

Mass of water from reaction = ?

Step 2: Write statement for conversion

Given equation shows that

1 mole of H₂SO₄ gives 2 moles of water

Step 3: Convert moles into molar mass

Convert the moles into molar mass so, the statement becomes,

98 g of H₂SO₄ gives (2)(18) g of water

1 g of H₂SO₄ gives (2)(18)/98 g of water

Step 4: Use given data

24.1 g of H₂SO₄ gives (2)(18)(24.1)/98 g of water

amount of water = 8.85 g

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4 years ago

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The low-grade iron ore taconite, which contains Fe3O4, is concentrated and made into pellets for processing. If one ton of tacon

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Answer: The percent composition of $Fe_3O_4$ in taconite is 37.6 %.

Explanation:

We are given:

Mass of taconite pellets = 1 ton = 907185 g (Conversion factor: 1 ton = 907185 g)

Mass of iron produced = 545 lb = 247212 g (Conversion factor: 1 lb = 453.6 g )

We know that:

Molar mass of iron = 55.85 g/mol

Molar mass of $Fe_3O_4$ = 231.53 g/mol

1 mole of $Fe_3O_4$ contains 3 moles of iron atom and 4 moles of oxygen atom

(3 × 55.85) = 167.55 g of iron is produced from 231.53 grams of $Fe_3O_4$

So, 247212 grams of iron will be produced from = $\frac{231.53}{167.55}\times 247212=341611.43g$ of $Fe_3O_4$

To calculate the percentage of $Fe_3O_4$ in taconite, we use the equation:

$\%\text{ composition of }Fe_3O_4=\frac{\text{Mass of }Fe_3O_4}{\text{Mass of taconite}}\times 100$

Mass of taconite = 907185 g

Mass of $Fe_3O_4$ = 341611.43 g

Putting values in above equation, we get:

$\%\text{ composition of }Fe_3O_4=\frac{341611.43g}{907185g}\times 100=37.6\%$

Hence, the percent composition of $Fe_3O_4$ in taconite is 37.6 %.

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3 years ago

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3 years ago

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How many grams of Sg is required to produce 83.10 g SF6? S: +24F-->8SF

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Answer : The mass of $S_8$ required is 18.238 grams.

Explanation : Given,

Mass of $SF_6$ = 83.10 g

Molar mass of $SF_6$ = 146 g/mole

Molar mass of $S_8$ = 256.52 g/mole

The balanced chemical reaction is,

$S_8+24F_2\rightarrow 8SF_6$

First we have to determine the moles of $SF_6$ .

$\text{Moles of }SF_6=\frac{\text{Mass of }SF_6}{\text{Molar mass of }SF_6}=\frac{83.10g}{146g/mole}=0.569moles$

Now we have to determine the moles of $S_8$ .

From the balanced chemical reaction we conclude that,

As, 8 moles of $SF_6$ produced from 1 mole of $S_8$

So, 0.569 moles of $SF_6$ produced from $\frac{0.569}{8}=0.0711$ mole of $S_8$

Now we have to determine the mass of $S_8$ .

$\text{Mass of }S_8=\text{Moles of }S_8\times \text{Molar mass of }S_8$

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4 years ago

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Answer:

The total energy of the photons detected in one hour is 7.04*10⁻¹¹ J

Explanation:

The energy carried by electromagnetic radiation is displaced by waves. This energy is not continuous, but is transmitted grouped into small "quanta" of energy called photons. The energy (E) carried by electromagnetic radiation can be measured in Joules (J). Frequency (ν or f) is the number of times a wave oscillates in one second and is measured in cycles / second or hertz (Hz). The frequency is directly proportional to the energy carried by a radiation, according to the equation: E = h.f, (where h is the Planck constant = 6.63 · 10⁻³⁴ J / s).

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$f=\frac{speed of light}{wavelength}$