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Kitty [74]
3 years ago
5

The data were collected over five spring seasons. What is the difference between the number of frogs in the pond when the rainfa

ll was 5 cm and when the rainfall was 20 cm?
Please help​
Chemistry
1 answer:
Lunna [17]3 years ago
3 0

Answer: they like deep water

Explanation: they do

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Calculate the maximum numbers of moles and grams of iodic acid (HIO₃) that can form when 635 g of iodine trichloride reacts with
poizon [28]

What is Chemical Reaction?

A chemical reaction occurs when a certain group of molecules converts into another form without affecting their nuclei; only the transfer or sharing of electrons and the building and breaking of bonds occur.

Main Content

Known :

\mathrm{ICl}_{3}+\mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+\mathrm{HCl}

Mass of ICI_3 = 635g

Mass of H_2O = 118.5g

Calculations :

First, balance the given chemical equation by place 2,3 and 5 as the coefficients of ICI_3, H_2O and HCl,\\ Respectively

2 \mathrm{ICl}_{3}+3 \mathrm{H}_{2} \mathrm{O} \longrightarrow \mathrm{ICl}+\mathrm{HIO}_{3}+5 \mathrm{HCl}

We multiply the given mass of ICl_3 by the reciprocal of its molar mass to get the number of moles. The molar mass of ICl_3 is 233.26g/mol

\text { Moles of } \mathrm{ICl}_{3}=635 \mathrm{~g} \mathrm{ICl}_{3} \times \frac{1 \mathrm{~mol} \mathrm{ICl}_{3}}{233.26 \mathrm{~g} \mathrm{ICl}_{3}}=2.7223 \mathrm{~mol}  \mathrm{ICl}_{3}

Them, we multiply the ratio between ICl_3 and HIO_3. based on the chemical equation, the molar ratio 1 mol HIO_3/2  mol ICl_3.

\text { Moles of } \mathrm{HIO}_{3} \text { formed }=2.7223 \mathrm{~mol} \mathrm{ICl}_{3} \times \frac{1 \mathrm{~mol} \mathrm{HIO}_{3}}{2 \mathrm{~mol} \mathrm{ICl}_{3}}=1.3612 \mathrm{~mol} \mathrm{HIO}_{3}

For water, we again multiply the given mass H_2O by the reciprocal of its molar mass to get the number if moles. The molar mass of H_2O is 18.02g/mol

\text { Moles of } \mathrm{H}_{2} \mathrm{O}=118.5 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} \times \frac{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{18.02 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}}=6.5760 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}

Then, we multiply the molar ratio between H2O and HIOs. Based on the chemical equation, the molar ratio is 1 mol HIO_3/3 Mole H_2O

\text { Moles of } \mathrm{HIO}_{3} \text { formed }=6.5760 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O} \times \frac{1 \mathrm{~mol} \mathrm{HIO}_{3}}{3 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}=2.1920 \mathrm{~mol} \mathrm{HIO}_{3}

We can see that the limiting reactant is ICL_3 since the given mass of ICl_3 forms lesser product than water does. Thus , the maximum number of moles of HIO_3 formed is 1.36 mol HIO_3. We now multiply the molar mas of HIO_3 to the calculated number of moles. The molar mass of HIO_3 is 175.91 g/mol.

Mass of HIO_3 formed (Max) =1.3612 \mathrm{~mol} \mathrm{HIO}_{3} \times \frac{175.91 \mathrm{~g} \mathrm{HIO}_{3}}{1 \mathrm{~mol} \mathrm{HIO}}=239 \mathrm{~g} \mathrm{HIO}_{3}

We multiply the number of moles of ICl_3 by the molar ratio between ICl_3 and H_2O which is 3 mol H_2O mol ICl_3 we get the number of moles of H_2O reacted. Then, we multiply the molar mass of water.

Mass of H_2O reacted =2.7223 \mathrm{~mol} \mathrm{ICl} 3 \times \frac{3 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}{2 \mathrm{~mol} \mathrm{ICl}_{3}} \times \frac{18.02 \mathrm{~g} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{~mol} \mathrm{H}_{2} \mathrm{O}}

Mass of H_2O reacted = 73.6g H_2O

We subtract the mass of H_2O reacted from the given mass of H_2O.

Mass of H_2O = 118.5 - 73.6g = 44.9g H_2O

To learn more about Chemical Reaction

brainly.com/question/11231920

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2 years ago
What is the definition of relief in science terms
SOVA2 [1]
The apparent topography exhibited by minerals in thin section as a consequence of refractive index.
6 0
4 years ago
What are some examples of how matter moves through a cycle on earth ​
olganol [36]

Answer:

Ocean, lakes and rivers. Are all liquids.

Explanation:

Ocean, lakes and rivers. Are all liquids. Snow starts off as a liquid, evaporates into a gas and camoes back as snow.

4 0
4 years ago
PLEASE HELP ME!!!!!
Oxana [17]
The second one is correct im pretty sure
3 0
4 years ago
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A 37.2-g sample of lead (Pb) pellets at 20°C is mixed with a 62.7-g sample of lead pellets at the same temperature. What are th
Vesnalui [34]

Answer:

Mass of sample is 99.9 g, density of ample is 11.35 g/cm^{3} and temperature of sample is 20^{0}\textrm{C}

Explanation:

Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.

Mass of combined sample = (37.2+62.7) g = 99.9 g

Density is an intensive property. Therefore density of combined sample of lead will be same as with density of Pb.

Density of combined sample = 11.35 g/cm^{3}

Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.

temperature of combined sample = 20^{0}\textrm{C}

8 0
3 years ago
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