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Kitty [74]
3 years ago
5

The data were collected over five spring seasons. What is the difference between the number of frogs in the pond when the rainfa

ll was 5 cm and when the rainfall was 20 cm?
Please help​
Chemistry
1 answer:
Lunna [17]3 years ago
3 0

Answer: they like deep water

Explanation: they do

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The equilibrium constant, K, for the following reaction is 5.10X10 at 548 K. NH_CH(s) 2 NH3(E) + HC1(2) Calculate the equilibriu
Serga [27]

Answer:

The equilibrium concentration of HCl is 0.01707 M.

Explanation:

Equilibrium constant of the reaction = K_c=5.10\times 10^{-6}

Moles of ammonium chloride = 0.573 mol

Concentration of ammonium chloride = \frac{0.573 mol}{1.00 L}=0.573 M

     NH_4HCl(s)\rightleftharpoons 2 NH_3(g) + HCl(g)

Initial:            0.573     0           0

At eq'm:      (0.573-x)   x           x

We are given:

[NH_4Cl]_{eq}=(0.573-x)

[HCl]_{eq}=x

[NH_3]_{eq}=x

Calculating for 'x'. we get:

The expression of K_{c} for above reaction follows:

K_c=\frac{[HCl][NH_3]}{[NH_4Cl]}

Putting values in above equation, we get:

5.10\times 10^{-6}=\frac{x\times x}{(0.573-x)}

2.9223\times 10^{-6}-5.10x\times 10^{-6}=x^2

x^2-2.9223\times 10^{-6}+(5.10\times 10^{-6})x=0

On solving this quadratic equation we get:

x = 0.01707 M

The equilibrium concentration of HCl is 0.01707 M.

3 0
3 years ago
Epsom salt is commonly purchased in the pharmacy for a variety of uses, anti-inflammatory, laxative, and cosmetic. epsom salt is
Dominik [7]
Epsom salt is MgSO4.
We assume x water of hydration in the crystalline form.

Molecular mass of MgSO4 = 24+32+4*16=120
Molecular mass of MgSO4.xH2O = 120+18x

By proportion, 
2.000/0.977 = (120+18x)/120
Cross multiply
0.977(120+18x) = 120*2.000
from which we solve for x
17.586x+117.24 = 240
x=122.78/17.586
=6.980

Answer: there are 7 water of hydration in Epsom salt, according to the experiment.

Note: more accurate (proper) results may be obtained by using exact values (3-4 significant figures) in the molecular masses.  However, since water of hydration is the nearest integer, using approximate values (to at least two significant figures) suffice.
4 0
3 years ago
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Calculate the amount, in moles, of each of the following. You may round atomic masses to one decimal place.
Vlada [557]

Answer:

The answer to your question is:

a) 0.023 mol of CdS

b) 0.12 mol of MoO3

c) 7.3 mol of AlPO4

Explanation:

a) CdS

MW = 112.4 + 32

      = 144 g

                                144g ------------------ 1 mol

                                  3.28g --------------  x

                                 x = (3.28 x 1) / 144

                                 x = 0.023 mol

b) MoO3

MW = 96 + 3(16) = 144 g

                              144g -------------------  1 mol

                               17.5g -----------------   x

                               x = (17.5 x 1) / 144

                               x = 0.12 mol

c) AlPO4

MW = 27 + 31 + 4(16)

MW = 122 g

                            122 g ------------------  1mol

                            890 g ------------------   x

                            x = (890 x 1) / 122

                            x = 7.3 mol of AlPO4

7 0
3 years ago
Correctly order the production and transport of sperm through the male reproductive system. Semen is released from the penis, Sp
Scilla [17]
1) Sperm is produced in the testes. 2) sperm leaves the testes through the seamen duct, 3) in the seaman duct fluids from the glands are added to the Sperm, 4) seaman is released form the penis.
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2 years ago
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What are the things you get taught in 6th grade science?
klasskru [66]
Stuff about the earth and tectonic plates, and about space and stuff.
8 0
3 years ago
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