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Kitty [74]
3 years ago
5

The data were collected over five spring seasons. What is the difference between the number of frogs in the pond when the rainfa

ll was 5 cm and when the rainfall was 20 cm?
Please help​
Chemistry
1 answer:
Lunna [17]3 years ago
3 0

Answer: they like deep water

Explanation: they do

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omeli [17]
When things explode
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2 years ago
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the reaction of two gases in a sealed container produces a different gas and the system reaches equilibrium. what change in conc
telo118 [61]

Answer: Increasing the concentration of a reactant or decreasing the concentration of the product.

Explanation: For the equilibrium of the reaction to shift to the left, we must decrease the concentration of a reactant or increase the concentration of the product. This is based on Le Chatelier's principle which describes the effect on the equilibrium of changes in concentration or pressure of a product or a reactant. Adding more products in a system would disturb the equilibrium thus it would cause to reestablish it by shifting the reaction to the left producing the reactants. This would also be the same when you decrease the number of reactants in the system.

5 0
3 years ago
Ions Types of Ions Cation Anion 1. H+ 2.O-2 3.Ba2+ 4.Br- 5.Hg2+ 6.Li+ 7.Ca2+ 8.F- 9.S-2 10.Fe3+
fiasKO [112]

Explanation:

The species with a positive charge over it, which means lack of electrons are called cations. Whereas the species with negative over it, meaning it has an excess of electrons with it are called anions.

From the list given the cations are

H+, Ba2+, Hg2+, Li+, Ca2+ and Fe2+

Whereas anions from the list are

O-2, Br-5, F-, S-2.

A Combination of cation and anions make an ionic compound in which cation is written first and then anion.

6 0
2 years ago
A 4.305-g sample of a nonelectrolyte is dissolved in 105 g of water. the solution freezes at -1.23c. calculate the molar mass of
amid [387]
The answer is 62.00 g/mol. 
Solution: 
Knowing that the freezing point of water is 0°C, temperature change Δt is 
     Δt = 0C - (-1.23°C) = 1.23°C 
Since the van 't Hoff factor i is essentially 1 for non-electrolytes dissolved in water, we calculate for the number of moles x of the compound dissolved from the equation 
     Δt = i Kf m 
     1.23°C = (1) (1.86°C kg mol-1) (x / 0.105 kg) 
     x = 0.069435 mol 
Therefore, the molar mass of the solute is  
     molar mass = 4.305g / 0.069435mol = 62.00 g/mol
6 0
2 years ago
If the mass of 23 gummi bears is 49.2g, what is the average mass of one gummi bear? Round answer to the nearest 0.00g (do NOT ty
Mila [183]

just divide the mass 49.2 grams by the amount of gummi bears 23 to get the answer of 2.1391 then it says to round to 2 decimals so 2.14 grams

3 0
3 years ago
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