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ladessa [460]
2 years ago
8

PLEASE HELP ME I NEED HELP

Chemistry
1 answer:
Crazy boy [7]2 years ago
4 0

Answer:

<u>5 moles S x (36.02 g S/mole S) = 180.1 grams of S</u>

Explanation:

The periodic table has mass units for every element that can be correlated with the number of atoms of that element.  The relationship is known as Avogadro's Number.  This number, 6.02x10^{23} , is nicknamed the mole, which scientists found to be a lot more catchy, and easier to write than  6.02x10^{23}.  <u>The mole is correlated to the atomic mass of that element.</u>  The atomic mass of sulfur, S, is 36.02 AMU, atomic mass units.  <u>But it can also be read as 36.02 grams/mole.</u>

<u></u>

<u>This means that 36.02 grams of S contains 1 mole (6.02x</u>10^{23}<u>) of S atoms</u>.

<u></u>

This relationship holds for all the elements.  Zinc, Zn, has an atomic mass of 65.38 AMU, so it has a "molar mass" of 65.38 grams/mole.  ^5.38 grams of Zn contains 1 mole of Zn atoms.  

And so on.

5.0 moles of Sulfur would therefore contain:

(5.0 moles S)*(36.02 grams/mole S) = <u>180.1 grams of S</u>

Note how the units cancel to leaves just grams.  The units are extremely helpful in mole calculations to insure the correct mathematical operation is done.  To find the number of moles in 70 g of S, for example, we would write:

(70g S)/(36.02 grams S/mole S) = 1.94 moles of S.  [<u>Note how the units cancel to leave just moles</u>]

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Answer:

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Explanation:

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Similarly, CH3OH  possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.

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Consider the balanced equation for the following reaction:
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Answer:

In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.

Explanation:

Step 1: Data given

Mass of HCl = 69.0 grams

Mass of Al = 78.0 grams

Molar mass HCl = 36.46 g/mol

Atomic mass Al = 26.99 g/mol

Step 2: The balanced equation

6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)

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Moles Al = 2.89 moles

Step 5: Calculate the limiting reactant

For 6 moles HCl we need 2 moles Al  to produce 3 moles H2 and 2 moles AlCl3

HCl is the limiting reactant. It will completely be consumed (1.89 moles). Aluminium is the reactant in excess. There will react 1.89 / 3 = 0.63 moles

There will remain 2.89 - 0.63 = 2.26 moles aluminium

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