<span>The Keq expression for I2(s) + H2O(l) H + (aq) + I-(aq) + HOI(aq) equilibrium is
H2(g) + I2(g) <----> 2 HI(g).In this Keq expression hydrogen reacts with iodine gives Hydrogen Iodide.HI is a diatomic molecule and it is one of the primary source of iodine which act as a reducing agent.Totally it is the reverse chemical equilibrium reaction.</span>
Answer:
NH3 ------dipole - dipole forces
CH3OH ------ dipole - dipole forces
AlBr3 ------- ion - dipole forces
AlCl3 ------- ion - dipole forces
Explanation:
Let us recall that water is a polar molecule. This means that water has a positive as well as a negative end. NH3 also has a dipole. The interaction between solute and solvent dipoles leads to the dissolution of NH3 in water. Hence the strongest intermolecular force here is dipole - dipole forces.
Similarly, CH3OH possesses a polar -O-H group which can interact with water via dipole - dipole interaction as its strongest intermolecular force.
As for AlBr3 and AlCl3, the two substances dissociate into ions in solution and these ions interact with the dipole in water via ion - dipole interaction as its strongest intermolecular interaction.
White because it has left volume but alot more matter
Answer:
In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.
Explanation:
Step 1: Data given
Mass of HCl = 69.0 grams
Mass of Al = 78.0 grams
Molar mass HCl = 36.46 g/mol
Atomic mass Al = 26.99 g/mol
Step 2: The balanced equation
6HCl(aq) + 2Al(s) → 3H2(g) + 2AlCl3(s)
Step 3: calculate moles HCl
Moles HCl = mass HCl / molar mass HCl
Moles HCl = 69.0 grams / 36.46 g/mol
Moles HCl = 1.89 moles
Step 4: Calculate moles Al
Moles Al = 78.0 grams / 26.99 g/mol
Moles Al = 2.89 moles
Step 5: Calculate the limiting reactant
For 6 moles HCl we need 2 moles Al to produce 3 moles H2 and 2 moles AlCl3
HCl is the limiting reactant. It will completely be consumed (1.89 moles). Aluminium is the reactant in excess. There will react 1.89 / 3 = 0.63 moles
There will remain 2.89 - 0.63 = 2.26 moles aluminium
In this reaction HCl is the limiting reactant and aluminium is the reactant in excess.
Answer:
i think the answers C: Thermalizing but if its not im sorry :/
Explanation: