Question

The gas begins with a temperature of 333 K and a pressure of 4.00 atm that increases to 7.65 atm as the gas is heated. What is the temperature of the gas when the pressure increases to 7.65 at?

Answer 1

The final temperature on increasing the pressure to 7.65 atm is 637 K.

Explanation:

The relation between temperature attained by gas molecules at varying pressure is defined by Guy-Lusac's law. It states that at constant volume, the pressure experienced by the gas molecules is directly proportional to the temperature attained by those molecules.

P∝T

Here, the initial pressure P₁ is given as 4 atm at temperature T₁ = 333 K, then the final pressure P₂ = 7.65 atm can be attained at temperature T₂.

The final temperature should be greater than the initial temperature as there is an increase in the pressure.

So,

$\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

$\frac{4}{333} =\frac{7.65}{T_{2} } \\\\T_{2} =\frac{7.65*333}{4} = 636.8 =637 K$

Hence, the final temperature on increasing the pressure to 7.65 atm is 637 K.