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3 years ago

How is the number of electrons in an element determined?

Chemistry

2 answers:

scoray [572]3 years ago

6 0

Answer:

By finding the number of protons

Explanation:

Keep in mind when trying to find the number of electrons of a element, the number of electrons also equals the number of protons. In order to find the number of protons in the element simply find it's atomic number.

Example:

Find the number of electrons in the element iron.

Fe (Iron)

Fe's atomic number is 26

Protons/electrons = 26

Hope this helps.

elixir [45]3 years ago

3 0

The number of protons, neutrons, and electrons in an atom can be determined from a set of simple rules. The number of protons in the nucleus of the atom is equal to the atomic number (Z). The number of electrons in a neutral atom is equal to the number of protons.

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Which correctly describes the laws of conservation?

VashaNatasha [74]

A is the answer

Venn diagrams are used for comparing and contrasting different topics. The overlapping sections show characteristics that the topics have in common, and the sections that are unique to each topic show the characteristics apply to only that topic.

5 0

3 years ago

How many liters of oxygen are required to react completely with 1.2 liters of hydrogen to form water? 2H2(g) + O2(g) → 2H2(g)

Ira Lisetskai [31]

Answer:

$\boxed{\text{0.60 L}}$

Explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.

1. Write the chemical equation.

Ratio: 2 L 1 L

2H₂ + O₂ → 2H₂O

V/L: 1.2

2. Calculate the volume of O₂.

According to Gay-Lussac, 1 L of O₂ forms from 2 L of H₂.

Then, the conversion factor is (1 L O₂/2 L H₂).

$\text{Volume of O}_{2} = \text{1.20 L H}_{2}\times \dfrac{\text{1 L O}_{2}}{\text{2 L H}_{2}} = \textbf{0.60 L O}_{2}\\\\\text{You need }\boxed{\textbf{0.60 L of O}_{2}}$

4 0

3 years ago

An open end mercury manometer was constructed from a u-shaped tube. in a particular measurement, the level in the end connected

aev [14]

We can solve this problem using the formula:

P2 – P1 = ρ g (h2 – h1)

where,

P2 = pressure of the gas manifold = ?

P1 = pressure of the outside air = 754 torr = 100,525 Pa

ρ = density of mercury = 13560 kg/m^3

h2 = height in gas manifold = 76.2 cm = 0.762 m

h1 = height in air = 23.8 cm = 0.238 m

So w can directly find for P2:

P2 = 13560 * 9.81 * (0.762 – 0.238) + 100,525

P2 = 170,229.37 Pa

Convert back to torr:

<span>P2 = 170,229.37 Pa = 1276.83 torr (ANSWER)</span>

7 0

3 years ago

Please fill out correctly<br> 15POINTS

ryzh [129]

Answer:

The answer to your question is below

Explanation:

I will write the answers assigning numbers to each column

Isotope Nuclear form 1 2 3 4 5

Boron-10 ¹⁰B 5 10 5 5 5

Potassium-37 ³⁷K 19 37 19 18 19

Boron-11 ¹¹B 5 11 5 6 5

Silver-107 ¹⁰⁷Ag 47 107 47 60 47

Uranium-238 ²³⁸U 92 238 92 146 92

Oxygen-17 ¹⁷O 8 17 8 9 8

Silver-108 ¹⁰⁸Ag 47 108 47 61 47

4 0

3 years ago

Which metalloids would behave more like metals? Which metalloids would behave more like nonmetals?.

joja [24]

The metalloid that tends to act more like metals is boron.

The metalloids that tend to act more like nonmetals are arsenic, antimony, and tellurium.

Metals are the elements that have the ability to lose electrons, while nonmetals are the elements with the ability to gain electrons.

<h3>Metalloids, Metals, and Nonmetals</h3>

The metalloids are the elements with the ability to act as both metals and nonmetal. The metalloids have wide application, with its characteristic in between metals and nonmetals.

The metalloids with less than 4 electrons in the valence shell tends to act like metals, while metalloids with more than 4 valence electrons tends to act more like nonmetals.

The metalloid that tends to act more like metals is boron.

The metalloids that tend to act more like nonmetals are arsenic, antimony, and tellurium.

Learn more about metalloids, here:

brainly.com/question/17482288

5 0

3 years ago

Read 2 more answers