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Katena32 [7]
4 years ago
10

Raymond was riding a zip-cable from the top of a viewing post. The cable is 70 yards long. The viewing post is 56 yards high and

forms a right angle with the ground, as shown in the picture below. Note: Figure is not drawn to scale. Given this information, how far is the bottom of the cable from the base of the viewing post? A. 84 yards B. 28 yards C. 42 yards D. 56 yards
Mathematics
1 answer:
Marysya12 [62]4 years ago
8 0

Answer:

C. 42 yards

Step-by-step explanation:

You may recognize this as a 3-4-5 right triangle with a scale factor of 14. The two given sides are 5·14 = 70 and 4·14 = 56. Then the missing side is 3·14 = 42.

If not, you can use the Pythagorean theorem in the usual way:

... hypotenuse² = leg1² +leg2²

... 70² = 56² +leg2²

... leg2 = √(70² -56²) = √1764 = 42 . . . . yards

The cable is anchored 42 yards from the  base of the tower.

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<h3>How to calculate the width?</h3>

From the complete information, the other two sides have been given as 4 inches and 5 inches.

The Pythagoras theorem will be used in this case and it goes thus:

4² + Width² = 5²

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3 years ago
Find a ·<br> b. |a| = 80, |b| = 50, the angle between a and b is 3π/4.
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Answer:

a\cdot b=-2000\sqrt{2}

Step-by-step explanation:

Given information: |a| = 80, |b| = 50, the angle between a and b is 3π/4.

We need to find the dot product  a · b.

The formula of dot product is

a\cdot b=|a||b|\cos \theta

where, θ is the angle between a and b.

Substitute the given values in the above formula.

a\cdot b=(80)(50)\cos (\frac{3\pi}{4})

a\cdot b=4000\cos (\pi-\frac{\pi}{4})

a\cdot b=-4000\cos (\frac{\pi}{4})           [\because \cos (\pi-\theta)=-\cos \theta]

a\cdot b=-4000\frac{1}{\sqrt{2}}

a\cdot b=-\frac{4000}{\sqrt{2}}

Rationalize the above equation.

a\cdot b=-\frac{4000}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}

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