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MArishka [77]
3 years ago
6

If 1.87 g‎ of acetic acid (ch3co2h)‎ reacts with 2.31 g‎ of isopentylalcohol (c5h12o)‎ to give‎ 3.20 g of isopentylacetate (c7h1

4o2)‎, what is the percent yield of the reaction?
Chemistry
1 answer:
Orlov [11]3 years ago
8 0

The reaction of acetic acid with isopentyl alcohol is

CH3COOH + C5H12O  ---> C7H14O2  + H2O

Thus one mole of acetic acid reacts with one mole of isopentyl alcohol to give one mole isopentyl acetate

Molar mass of acetic acid = 60.05 g / mole

Moles of acetic acid used = Mass used  / Molar mass = 1.87/ 60.05 = 0.0311

Molar mass of isopentyl alcohol = 88.15 g / mole

Moles of isopentyl alcohol = Mass / Molar mass = 2.31 / 88.15 = 0.0262

Molar mass of isopentyl acetate = 130.19 g / mole

Moles of isopentyl acetate = 3.20 / 130.19 = 0.0246

As per equation 0.0262  should of isopentyl alcohol should react with 0.0262 moles of acetic acid to give 0.0262 isopentyl acetate

Thus theoretical yield = 0.0262 moles

Actual yield = 0.0246

% yield = Actual yield X 100 / theoretical yield = 0.0246 X 100 / 0.0262 = 93.89%

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448 K is the final temperature of the water.

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The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

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Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

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197 kJ = 316 g x 4.18 J/Kg x (T_{finals} - T_ {initial})

197 kJ = 316 g x 4.18 J/Kg x ( T_{finals}-298 K)

0.1491429956 x 1000 =  T_{finals}-298 K

149.1429956 + 298 = T_{finals}

447.1429956 = T_{finals}

448 K = T_{finals}

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5 0
2 years ago
What mass of oxygen is contained in a 5.8 g sample of NaHCO3?
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A 2.0 molal sugar solution has approximately the same freezing point as 1.0 molal solution of 1) CaCl2 2) CH3COOH 3) NaCl 4) C2H
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