Question

23 grams of sodium reacts with 293 cm 3 of water that is initially at 298 k. it produces an enthalpy change of 197 kj. what is the final temperature of the water? the specific heat capacity of water is 4.18 j/k g.

Answer 1

448 K is the final temperature of the water.

What is specific heat capacity?

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

Given,

the mass of Na is 23 g

The volume of water = 293 cm3

Mass of water = 293 g

Total solution mass = 23 g + 293 g = 316 g

Specific heat capacity of water = 4.18 J/Kg

The equation relating mass, heat, specific heat capacity and temperature change is:

q = mcΔT

197 kJ = 316 g x 4.18 J/Kg x ($T_{finals} - T_ {initial}$)

197 kJ = 316 g x 4.18 J/Kg x ( $T_{finals}$-298 K)

0.1491429956 x 1000 =  $T_{finals}$-298 K

149.1429956 + 298 = $T_{finals}$

447.1429956 = $T_{finals}$

448 K = $T_{finals}$

Hence, 448 K is the final temperature of the water.

What does a high specific heat capacity mean?

A high specific heat capacity means that it can store a large amount of thermal energy for a small change in mass or temperature.

Learn more about specific heat capacity here:

brainly.com/question/2530523

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