CH4 + 202 → CO2 + 2H2O
How many grams of O2 produced from 2 moles of H20?
2 answers:
<h3>Answer:</h3>
60 g O₂
<h3>General Formulas and Concepts:
</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>Explanation:
</h3>
<u>Step 1: Define</u>
[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O
[Given] 2 mol H₂O
[Solve] x g O₂
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol H₂O → 2 mol O₂
[PT] Molar Mass of O - 16.00 g/mol
Molar Mass of O₂ - 2(16.00) = 32.00 g/mol
<u>Step 3: Stoichiometry</u>
- Set up conversion:

- Divide/Multiply:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 1 sig fig.</em>
64.00 g O₂ ≈ 60 g O₂
Mass of O₂= 64 g
<h3>
Further explanation
</h3>
Given
Reaction
CH₄ + 20₂ → CO₂ + 2H₂O
2 moles of H₂O
Required
Mass of O₂
Solution
In a chemical equation, the reaction coefficient shows the mole ratio of the compounds involved in the reaction, reactants or products
From the equation, mol ratio of H₂O : O₂ = 1 : 1, so moles O₂ :
= 1/1 x moles H₂O
= 1/1 x 2
= 2 moles
Mass of O₂ :
= mol x MW
= 2 x 32 g/mol
= 64 g
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