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andreev551 [17]
2 years ago
13

I need help in science

Chemistry
1 answer:
astraxan [27]2 years ago
7 0
The answer is D . I hope this help you :) .
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The strength of gravitational force depends on ___.
MrRissso [65]

Answer:

c.mass and distance

Explanation:

gravitation=mass/distance ²

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A sub-shell with n = 6, l = 2 can accommodate a maximum of:
Mrrafil [7]

Answer:

72

Explanation:

2n^2

n=6

2(6)^2=2×36

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3 years ago
A 50.0 g sample of scandium, sc, is heated by exposure to 1.50 x 10 3 j. The temperature of the sc is raised by 61.1 o
statuscvo [17]

Given mass of Scandium = 50.0 g

Increase in temperature of the metal when heated = 61.1^{0}C

Heat absorbed by Scandium = 1.50*10^{3}J

The equation showing the relationship between heat, mass, specific heat and temperature change:

Q = m C (deltaT)

Where Q is heat = 1.50*10^{3}J

m is mass = 50.0 g

ΔT = 61.1^{0}C

On plugging in the values and solving for C(specific heat) we get,

1.50*10^{3}J=50.0g(C)(61.1^{0}C)

C = 0.491\frac{J}{g^{0}C }

Specific heat of the metal = 0.491\frac{J}{g^{0}C }

7 0
3 years ago
What is the mass percent of nitrogen in:<br><br> 1. N2O<br> 2. NO<br> 3. NO2<br> 4. N2O2
Temka [501]
We’re going to use the mass percent formula shown below:



For the percent by mass N, we’re going to rewrite the equation as:

98% (271 ratings)
View Complete Written Solution
Problem Details
Calculate the mass percent composition of nitrogen in each nitrogen-containing compound:

c. NO2
5 0
2 years ago
Give the Unabbreviated electron configuration for barium
Shalnov [3]

Answer:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

Step-by-step explanation:

Step 1. Locate barium in the Periodic Table.

It's in Period 6, Group 2: Element 56 (highlighted blue in the Periodic Table below).

Step 2. Add 54 electrons to the energy levels

You add then in the order shown in the diagram below.

The complete electron configuration is:

Ba: 1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

n =  2 +     8    +    8     +       18       +       18       +  2 = 56

8 0
3 years ago
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