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3 years ago

Help me with my test

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

5 0

Answer:c

Step-by-step explanation:

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A ______ is a rule that pairs each element in one set with exactly one element from a second set.

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Answer:

function

Step-by-step explanation:

A function is a rule that pairs each element in one set with exactly one element from a second set.

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3 years ago

Find the value of x. A = x B = x + 12 C = x - 9

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Step-by-step explanation:

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3 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

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3 years ago

Wat is 10,000 more than 6,310

ziro4ka [17]

To find 10,000 more than 6,310, you add; so the answer is 16,310

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3 years ago

ANSWER ASAP PLEASE FOR BRAINLIEST

adoni [48]

Answer:

Bottom= 3 Left side= 2.15 Right side= 1,775

Step-by-step explanation:

Divide every side by 4

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3 years ago

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