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Ket [755]
3 years ago
7

if it asks for scale factor does that mean i’m supposed to write a ratio? Can someone solve and explain these for me i’m so conf

used it’s GREATLY appreciated:)

Mathematics
1 answer:
STatiana [176]3 years ago
8 0
Yes scale factor means ratio. The height of the smaller pyramid to the larger pyramid in ratio form is 8:24 which simplifies to 1:3. The ratio of its areas is the scale factor squared, so 1^2:3^2=1:9. Since the surface area of the smaller pyramid is 124, the surface area of the larger pyramid must be 124x9. The ratio of volumes is the scale factor cubed, so 1^3:3^3=1:27. If the volume of the larger pyramid is 648, then the volume of the smaller pyramid is 1/27 of that, which equals 24.
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Prove theorems about triangles
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<em>a) impossible</em>

<em>b)  the sum of the angles in a triangle is 180°</em>

<em>63° + 59° + 57° = 179°</em>

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Step-by-step explanation:

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2 years ago
The students in the Go Green dub started a whool recling program. In
OlgaM077 [116]

Answer:

Students collected

  • 85+255=340 pounds of paper;
  • 18+90=108 pounds of cans;
  • 340+108=448 pounds of paper and cans combined in September and October.

Step-by-step explanation:

In September, the students collected 85 pounds of paper and 18 pounds of cans to recycle.

In October, their goal is to collect three times the amount of paper and five times the amount of cans they collected in September.

Hence, in October they collected

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In total, they collected

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3 0
3 years ago
Let P be a predicate. Determine whether or not each of the following implications is true and give a brief English explanation f
den301095 [7]

Answer:

See answer below

Step-by-step explanation:

1), Probably, your implication is ∀x∃yP(x,y)⇒∃x∀yP(x,y).

This implication is false. Consider the predicate P(x,y):="x<y" for real numbers x,y. Then, ∀x∃yP(x,y) is true: for all real x, there exists some y greater than x (take y=x+1 for example). However, ∃x∀yP(x,y) is false, as it would imply that there exists some real number x such that x is smaller than all real numbers, which is not true (real numbers do not have a minimum or a lower bound).

A short explanation would be, even if for all elements you can find one that makes a predicate true, you can not find one element that makes the predicate true for all elements.

2) Again, I assume that the predicate is ∃x∀yP(x,y)⇒∀x∃yP(x,y)

This implication is false. Consider the predicate P(x,y):="x is integer and xy=0 " for real numbers x,y. Then ∃x∀yP(x,y) is true, we need to take x=0. However, ∀x∃yP(x,y) is false, if you take x=1/2, 1/2 will never be an integer, no matter the value of y.

A short explanation would be, even if you can find one element that makes a predicate true for all elements, you can not always take an arbitrary element and find some element that makes the predicate true.

6 0
3 years ago
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