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snow_tiger [21]

3 years ago

10

Plane wall of material A with internal heat generation is insulated on one side and bounded by a second wall of material B, whic

h is without heat generation and is subjected to convection cooling. Find the inner (To) and outer surface (T1 and T2) temperatures of the composite.

1 answer:

viktelen [127]3 years ago

8 0

Sorry❤

Have a nice day ✨

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The parts of a feature control frame are the tolerance value, the datum references, and the

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d

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The asymmetric roof truss is of the type used when a near normal angle of incidence of sunlight onto the south-facing surface AB

marysya [2.9K]

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4 years ago

A wood pipe having an inner diameter of 3 ft. is bound together using steel hoops having a cross sectional area of 0.2 in^2. The

Minchanka [31]

Answers:

31.7 inches

Explanation:

Given:

Diameter = 3ft

Let D = Diameter

So, D = 3ft. (Convert to inches)

D = 3 * 12in = 36 inches

Coss-sectional area of the steel = 0.2in²

Gauge Pressure (P) = 4psi

Stress in Steel (σ)= 11.4ksi

Force in steel = ½ (Pressure * Projected Area)

Area (A) = 2 * Force/Pressure

Also, Area (A) = Spacing (S) * Wood Pipe Diameter

Area = Area

2*Force/Pressure = Spacing * Diameter

Substitute values I to the above expression

2 * Force / 4psi = S * 36 inches

Also

Force in steel (F) = Stress in steel (σ) × Cross-sectional area of the steel

So, F = 11.4ksi * 0.2in²

F = 11.4 * 10³psi * 0.2in²

F = 2.28 * 10³ psi.in²

So, 2 * Force / 4psi = S * 36 becomes

2 * 2.28 * 10³/4 = S * 36

S = 2 * 2.28 * 10³ / (4 * 36)

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5 0

4 years ago

25 gallons of an incompressible liquid exert a force of 70 lbf at the earth’s surface. What force in lbf would 6 gallons of this

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Answer:

froce by 6 gallon liquid on moon surface is 2.86 lbf

Explanation:

given data:

at earth surface

volume of an incompressible liquid = Ve = 25 gallons

force by liquid = 70 lbf

on moon

volume of liquid = Vm = 6 gallons

gravitational acceleration on moon is am = 5.51 ft/s2

Due to incompressibility , the density remain constant.

mass of liquid on surface of earth $= \frac{ force}{ acceleration}$

$mass = \frac{70lbf}{32.2 ft/s2}$

mass = 2.173 pound

$density \rho = \frac{mass}{volume}$

$= \frac{2.173}{25} = 0.0869 pound/ gallon$

froce by 6 gallon liquid on moon surface is

Fm = mass * acceleration

= density* volume * am

= 0.0869 *6* 5.51

= 2.86 lbf

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3 years ago

Blocks A and B each have a mass m. Determine the largest horizontal force P which can be applied to B so that A will not move re

slava [35]

Answer:

The answer is "15 N".

Explanation:

Please find the complete question in the attached file.

In frame B:

For just slipping:

$\to \frac{P}{2} \cos \theta =mg \sin \theta\\\\\to P=2 mg \tan \theta \\\\$

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4 0

3 years ago