Ask question

Ask question

All categories

snow_tiger [21]

3 years ago

10

Plane wall of material A with internal heat generation is insulated on one side and bounded by a second wall of material B, whic

h is without heat generation and is subjected to convection cooling. Find the inner (To) and outer surface (T1 and T2) temperatures of the composite.

1 answer:

viktelen [127]3 years ago

8 0

Sorry❤

Have a nice day ✨

You might be interested in

WILL BRAINLIEST IF CORRECT!!!!!<br><br> Some one help ASAP.

marin [14]

Answer:1.)envirmental protection agency(EPA)

2.)lens shade number

3.)source extraction ventalation

4.)personal safety/protective equipment

Explanation:

4 0

3 years ago

A teenage brain is already fully developed to enable us to manage risks effectively.

Kisachek [45]

Answer:

false

Explanation:

the brain is only really fully devolved by age 26

3 0

2 years ago

Read 2 more answers

Water at atmospheric pressure boils on the surface of a large horizontal copper tube. The heat flux is 90% of the critical value

masya89 [10]

Answer:

The tube surface temperature immediately after installation is 120.4°C and after prolonged service is 110.8°C

Explanation:

The properties of water at 100°C and 1 atm are:

pL = 957.9 kg/m³

pV = 0.596 kg/m³

ΔHL = 2257 kJ/kg

CpL = 4.217 kJ/kg K

uL = 279x10⁻⁶Ns/m²

KL = 0.68 W/m K

σ = 58.9x10³N/m

When the water boils on the surface its heat flux is:

$q=0.149h_{fg} \rho _{v} (\frac{\sigma (\rho _{L}-\rho _{v})}{\rho _{v}^{2} } )^{1/4} =0.149*2257*0.596*(\frac{58.9x10^{-3}*(957.9-0.596) }{0.596^{2} } )^{1/4} =18703.42W/m^{2}$

For copper-water, the properties are:

Cfg = 0.0128

The heat flux is:

qn = 0.9 * 18703.42 = 16833.078 W/m²

$q_{n} =uK(\frac{g(\rho_{L}-\rho _{v}) }{\sigma })^{1/2} (\frac{c_{pL}*deltaT }{c_{fg}h_{fg}Pr } \\16833.078=279x10^{-6} *2257x10^{3} (\frac{9.8*(957.9-0.596)}{0.596} )^{1/2} *(\frac{4.127x10^{3}*delta-T }{0.0128*2257x10^{3}*1.76 } )^{3} \\delta-T=20.4$

The tube surface temperature immediately after installation is:

Tinst = 100 + 20.4 = 120.4°C

For rough surfaces, Cfg = 0.0068. Using the same equation:

ΔT = 10.8°C

The tube surface temperature after prolonged service is:

Tprolo = 100 + 10.8 = 110.8°C

8 0

3 years ago

Design a decimal arithmetic unit with two selection variables, V1, and Vo, and two BCD digits, A and B. The unit should have fou

Bingel [31]

Ucsaaaaauxx627384772938282’cc ed un e uff ridicolizzarla +golfista

4 0

3 years ago

As the asteroid falls closer to the Earth's surface its _______ energy decreases and its _______ energy increases.

Levart [38]

Answer:

As the asteroid falls closer to the Earth's surface its <u>Gravitational</u> <u>Potential</u> energy <em>decreases</em> and its <u>Kinetic</u> energy <em>increases</em>.

4 0

3 years ago