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seropon [69]
3 years ago
15

A BOD test is run using 30 mL of wastewater and 270 mL of dilution water. The initial DO of the mixture is 9.0 mg/L. After 5 day

s, the DO is 4 mg/L. After 30 days, the DO in the bottle is 2 mg/L and it now longer seems to be dropping. At the beginning of the test, we added a nitrification inhibitor so we can assume that the nitrification is not occurring. Thus, the only BOD being measured is carbonaceous BOD
a) What is the BODs of the wastewater?
b) What is the ultimate carbonaceous BOD?
c) How much BOD remains after 5 days?
d) Based on the data above, estimate the reaction rate constant k (1/day)
Engineering
1 answer:
erma4kov [3.2K]3 years ago
3 0

D Hey will you please help me with my essay and I’ll get back to yours please ASAP
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A specimen of a 4340 steel alloy with a plane strain fracture toughness of 54.8 Mpa root m is exposed to a stress of 1030 MPa. W
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Answer:

It will not  experience fracture when it is exposed to a stress of 1030 MPa.

Explanation:

Given

Klc = 54.8 MPa √m

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Y = 1.0

This problem asks us to determine whether or not the 4340 steel alloy specimen will fracture when exposed to a stress of 1030 MPa, given the values of <em>KIc</em>, <em>Y</em>, and the largest value of <em>a</em> in the material. This requires that we solve for <em>σc</em> from the following equation:

<em>σc = KIc / (Y*√(π*a))</em>

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σc = 54.8 MPa √m / (1.0*√(π*0.5*10⁻³m))

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In the engineering design process, testing is the least important step.<br> True<br> False
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Explanation:

7 0
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Answer:

The second classmate is right.

Explanation:

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Ep = m * g * h

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h: height

When the train goes downwards the potential energy is converted into kinetic energy (manifested as speed) and when it climbs it consumes its kinetical energy. As long as no summit is taller than the first the train should have enough energy to climb them.

Also it must be noted that friction also consumes energy, and if the track is too lomg all the energy might be consumed by it.

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