Answer:
![a) 5n\\b) 10n\\c) 3n](https://tex.z-dn.net/?f=a%29%205n%5C%5Cb%29%2010n%5C%5Cc%29%203n)
Step-by-step explanation:
Let 'n' be any integer i.e. a number from the set {....., -3,-2,-1,0,1,2,3, ..... }
so 'n' can be termed as the variable here.
A number 'q' that can be divided by a a given number 'p' can be written as:
![n \times p](https://tex.z-dn.net/?f=n%20%5Ctimes%20p)
When divided by 'p' :
![\dfrac{q}{p} = \dfrac{n \times p}{p}\\\Rightarrow \dfrac{q}{p} = n](https://tex.z-dn.net/?f=%5Cdfrac%7Bq%7D%7Bp%7D%20%3D%20%5Cdfrac%7Bn%20%5Ctimes%20p%7D%7Bp%7D%5C%5C%5CRightarrow%20%5Cdfrac%7Bq%7D%7Bp%7D%20%3D%20n)
So, The number 'q' is completely divisible by 'p' leaving 'n' as the quotient.
Using this concept, let us solve the questions:
a) Using 'n' as the variable, a number that is divisible by 5 can be written as:
![5n](https://tex.z-dn.net/?f=5n)
b) Using 'n' as the variable, a number that is divisible by 10 can be written as:
![10n](https://tex.z-dn.net/?f=10n)
c) Using 'n' as the variable, a number that is divisible by 3 can be written as:
![3n](https://tex.z-dn.net/?f=3n)