To solve this problem you must follow the proccedure below:
a<span>. Find the perimeter and area of the cracker remaining:
The perimeter of a quarter circle is:
P=(</span>πr/2)+2r
P=(πx3 cm/2)+2(3 cm)
P=10.71 cm
The perimeter of <span>the cracker remaining is:
</span><span>
Pt=3 cm+6 cm+3 cm+10.71 cm
Pt=22.71 cm
The area of a quarter circle is:
A=</span>πr²/4
A=π(3 cm)²/4
A=7.06 cm²
<span>
The area of</span><span>of the cracker remaining is:
</span><span>
At=Area of a square-Area of quarter circle
At=L</span>²-(πr²/4)
At=(6 cm)²-(π(3 cm)²/4)
At=28.93 cm²
<span>
b. About how many bites can you get from the entire cracker?</span>
Number of bites=L²/(π(3 cm)²/4)
Number of bites=5
2(4+2x)25x+5 = 300x + 5
2(4+2)•25x+5
2(4+2)•25x=300x
= 300x + 5
Answer:
g=4
Step-by-step explanation:
If you're solving for g, you need to get it alone on one side. The way I did so was to subtract 7 from each side.
15 = 2g + 7
-7 -7
If you do that, the 7 on the right cancels out and you're left with 8 = 2g. To get the g alone, you divide it by it's base on both sides which in this case is 2.
8/2 = 2g/2
That will cancel the 2 out and will leave you with g on the right side and on the left side would be 4 because simple division (8/2=4)
Your final answer should be g = 4
Answer:
Read the problem out loud to yourself.
Draw a Picture.
Think “What do I need to find?”
List what is given.
Find the key words.
Solve.
Check your work.
Step-by-step explanation: Hopefully this helped!
