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Mathematics

1 answer:

Ulleksa [173]3 years ago

7 0

Answer:

Step-by-step explanation:

20 may be answer for this may be

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I need help with this problem

sesenic [268]

I hope this helps you

3 0

3 years ago

Solve the nonlinear system of equations. State the number of solutions.

WITCHER [35]

Answer:

Step-by-step explanation:

Hello,

Question 15

We can search x such that:

$x^2-4x+4=2x-5\\\\\text{*** subtract 2x-5 from both sides ***}\\ \\x^2-4x-2x+4+5=0\\ \\\text{*** simplify ***}\\ \\x^2-6x+9=0 \\ \\\text{*** we can notice a perfect square ***}\\ \\x^2 -2\cdot x \cdot 3 + 3^2=(x-3)^2=0\\\\\text{*** taking the root ***}\\\\x-3=0\\\\\large \boxed{\sf \ \ x=3 \ \ }$

There is 1 solution.

Question 16

Again, we search x such that:

$x^2-8x+15=2x-6\\\\\text{*** subtract 2x-6 from both sides ***}\\\\x^2-8x-2x+15+6=0\\\\\text{*** simplify ***}\\\\x^2-10x+21=0 \\ \\\text{*** we are looking for two roots where the sum is 10 and the product is 21 = 7 x 3 ***} \\\\x^2-7x-3x+21=x(x-7)-3(x-7)=(x-3)(x-7)=0\\\\\large \boxed{\sf \ \ x= 3 \ or \ x =7 \ \ }$ There are two solutions.