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3 years ago

Is (4, 7) a solution to the system of equations? Explain your answer.

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

4 0

Answer:

Step-by-step explanation:

Neither 4 or 7 is a solution to both equations

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Factor the expression. 35g^2 – 2gh – 24h^2

stiks02 [169]

Option C: $(7 g-6 h)(5 g+4 h)$ is the correct answer.

Explanation:

The given expression is $35 g^{2}-2 g h-24 h^{2}$

We need to determine the factor of the expression.

Now, let us break the given expression into two groups.

Hence, we get,

$35 g^{2}+28 g h-30 g h-24 h^{2}$

Simplifying, we get,

$\left(35 g^{2}+28 g h\right)+\left(-30 g h-24 h^{2}\right)$

Let us factor out 7g from the term $\left(35 g^{2}+28 g h\right)$

Hence, we have,

$7 g(5 g+4 h)+\left(-30 g h-24 h^{2}\right)$

Similarly, let us factor out -6h from the term $\left(-30 g h-24 h^{2}\right)$

Thus, we have,

$7 g(5 g+4 h)-6 h(5 g+4 h)$

Now, we shall factor out the term $5g+4h$ , we get,

$(7 g-6 h)(5 g+4 h)$

Thus, the factorization of the given expression is $(7 g-6 h)(5 g+4 h)$

Therefore, Option C is the correct answer.

3 0

3 years ago

Help!! Will give brainliest! Plz explain how to do this if possible.

Dima020 [189]

Answer: a=3.74

Step-by-step explanation:

first use 15 to solve for x and z. x=7.5 and z=12.99 or 13. Once you know x you can use that to solve for y and a. y=6.5 and x=7.5 and using pythagorean theorem you will find that a= the square root of 14 or 3.74.

4 0

3 years ago

Read 2 more answers

Find the volume of a cone with a base radius of 6 cm and a height of 10 cm write in terms of pie

Savatey [412]

Answer:

Volume of the cone is 120 π cm³

Step-by-step explanation:

Given that Base radius of cone is 6 cm and height is 10 cm and we need to find volume of the cone. Volume of cone is given by:

$\\ \: \: \dashrightarrow \: \: \: \underline{\boxed{\pmb{\sf{Volume_{(cone)} = \dfrac{1}{3} \pi r^2 h }}}} \\ \\$

On Substituting the required values, we get:

$\\ \: \: \dashrightarrow \: \: \sf \: Volume_{(cone)} = \frac{1}{3} \times \pi \times {(6)}^{2} \times 10 \\ \\ \\ \: \: \dashrightarrow \: \: \sf \: Volume_{(cone)} = \frac{1} {\cancel{3}} \times \pi \times \cancel{36} \times 10 \\ \\ \\ \: \: \dashrightarrow \: \: \sf \: Volume_{(cone)} = \pi \times 12 \times 10 \\ \\ \\ \: \: \dashrightarrow \: \: \sf \: \: { \purple{Volume_{(cone)} =120 \pi \: cm^3 }}\\ \\$