A feather is dropped on the moon from the height of 1.4m. The acceleration of gravity on the moon is 1.67ms-1. Determine the tim

Question

3 years ago

11

e for the feather to fall to the surface of the moon

1 answer:

Zinaida [17] · Answer 1 · 2022-03-05T02:02:32+03:00

1.3s

Explanation:

Given parameters:

Height = 1.4m

Gravity on moon = 1.67ms⁻¹

Unknown:

Time for feather to fall = ?

Solution:

To solve this problem, we are going to use one of the motion equation that relates time, gravity and height.

H = ut + $\frac{1}{2} g t^{2}$

Sine the body was dropped from rest, initial velocity is zero;

H = height

u = initial velocity

t = time

g = acceleration due to gravity

since u = 0;

H = $\frac{1}{2} g t^{2}$

1.4 = $\frac{1}{2}$ x 1.67 x t²

t = 1.3s

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