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Makovka662 [10]
3 years ago
12

COMPAWE APPLIANCENO STABILIZERREQUIRED* For 160V-260V power supply​

Physics
1 answer:
sergey [27]3 years ago
5 0

Answer:

cgyd6rvnfu ygoigvigceu fee duucdubr5vef8cuecyec

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a runner starts from rest and has an acceleration of 3 m/s^2. How fast is she running after 1.1 seconds
grigory [225]
Acceleration x time = velocity 

Since you're given acceleration and time, just plug the values into the equation. 

3\frac{m}{s^{2}} x 1.1 s = ? 

Solve that equation, and remember your velocity should be in m/s.
8 0
2 years ago
In which of the fire plume structure zones do the gases accelerate upward?
I am Lyosha [343]
The zone that gases always accelerate upward is the Luminous flame zone. The fire plume is the column of hot gases, flames and smoke rising above a fire. Gases accelerate upward toward the always luminous flame zone. The luminous flame height is the distance between the base of a flame and the point at which the plume is luminous half the time and transparent half the time.
3 0
3 years ago
A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift fo
Vinil7 [7]

Lift force exerted by the air on the rotors=143244 N

Explanation:

we use Newtons second law

F- (M+m)g=(M+m)a

F= lift force

m= mass of helicopter= 13000 Kg

M= mass of car= 2000 lb=907.2 kg

a= acceleration= 0.5 m/s²

g= acceleration due to gravity

F- (M+m)g=(M+m)a

F=(M+m)(a+g)

F=(13000+907.2)(0.5+9.8)

F=143244 N

8 0
3 years ago
(15 Points)
oksian1 [2.3K]

The vertical weight carried by the builder at the rear end is F = 308.1 N

<h3>Calculations and Parameters</h3>

Given that:

The weight is carried up along the plane in rotational equilibrium condition

The torque equilibrium condition can be used to solve

We can note that the torque due to the force of the rear person about the position of the front person = Torque due to the weight of the block about the position of the front person

This would lead to:

F(W*cosθ) = mgsinθ(L/2) + mgcosθ(W/2)

F(1cos20)= 197/2(3.10sin20 + 2 cos 20)

Fcos20= 289.55

F= 308.1N

Read more about vertical weight here:

brainly.com/question/15244771

#SPJ1

5 0
1 year ago
A piano tuner is using a 392 Hz tuning fork to tune the wire for a G-Natural note. She hears 4 beats per second. What are the tw
inysia [295]

A beat is an interference pattern between two sounds of slightly different frequencies, perceived as a periodic variation in volume whose rate is the difference of the two frequencies. Frequency beat is equal to,

f_{beat} =| f_2\pm f_1 |

The reference frequency in our case would be 392Hz, and since there is the possibility of the upper and lower range for the amount of beats per second that the two possible frequencies are heard would be

f_{beat} =|392+4|= 396Hz

f_{beat} =|392-4|=388Hz

Therefore the two possible frequencies the piano wire is vibrating at, would be 396Hz and 388Hz

5 0
3 years ago
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