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Makovka662 [10]
4 years ago
12

COMPAWE APPLIANCENO STABILIZERREQUIRED* For 160V-260V power supply​

Physics
1 answer:
sergey [27]4 years ago
5 0

Answer:

cgyd6rvnfu ygoigvigceu fee duucdubr5vef8cuecyec

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Calculate the energy transferred by an appliance using mains electricity (230V) if the charge is 150C. Give your answer in kiloj
Otrada [13]

The energy transferred by the appliance using mains electricity is 17.3 KJ

<h3>Data obtained from the question </h3>
  • Potential difference (V) = 230V
  • Charge (Q) = 150 C
  • Energy (E) =?

<h3>How to determine the energy transferred </h3>

The energy transferred can be obtained as follow:

E = ½QV

E = ½ × 150 × 230

E = 75 × 230

E = 17250 J

Divide by 1000 to express in kilojoules

E = 17250 / 1000

E = 17.3 KJ

Learn more about energy stored in a capacitor:

brainly.com/question/14739936

8 0
2 years ago
What is (a) the x component and (b) the y component of the net electric field at the square's center
Sav [38]

Answer:

What is (a) the x component and (b) the y component of the net electric field at the square's center

8 0
3 years ago
A car is traveling at 108 km/h, stuck behind a slower car. Finally the road is clear and the car pulls over to make a pass. The
mezya [45]

Answer:

The average acceleration of the car is 2.143 meters per square second.

Explanation:

Let assume that car accelerates uniformly, in that case, we can obtain the value of acceleration by using the following equation of motion:

v = v_{o}+a\cdot t

Where:

v_{o} - Initial velocity, measured in meters per second.

v - Final velocity, measured in meters per second.

a - Acceleration, measured in meters per square second.

t - Time, measured in seconds.

Now, we clear acceleration within expression:

a = \frac{v-v_{o}}{t}

Initial and final velocities are now converted from kilometers per hour into meters per second:

v_{o} = \left(108\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v_{o} = 30\,\frac{m}{s}

v = \left(135\,\frac{km}{h} \right)\cdot \left(1000\,\frac{m}{km} \right)\cdot \left(\frac{1}{3600}\,\frac{h}{s}  \right)

v = 37.5\,\frac{m}{s}

If we know that t = 3.5\,s, then, the average acceleration of the car is:

a = \frac{37.5\,\frac{m}{s}-30\,\frac{m}{s} }{3.5\,s}

a = 2.143\,\frac{m}{s^{2}}

The average acceleration of the car is 2.143 meters per square second.

8 0
3 years ago
(No files or links) Which of the following is a defining property of gases?
MariettaO [177]
The answer for this is d
6 0
3 years ago
A 450 N trunk rests on a 30 degree inclined plane. What is the force acting down the
Minchanka [31]

Answer: What is the force acting down the plane?

• Opp= hyp (sinq)= 450(sin30)= 225 N

• What is the force acting perpendicular to the plane?

• adj= hyp (cosq)= 450(cos30)= 390 N

Explanation:

4 0
3 years ago
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