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3 years ago

What is the meaning of insanity is relative

Physics

1 answer:

Luba_88 [7]3 years ago

6 0

Answer:

“Insanity is relative. It depends on who has who locked in what cage.” R.D. Laing: “Insanity – a perfectly rational adjustment to an insane world.” Nora Ephron: “Insane people are always sure that they are fine. It is only the sane people who are willing to admit that they are crazy.”Sep 20, 2012

Explanation:

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The force of attraction between a positive ion and a negative ion in an ionic<br> compound

Crazy boy [7]

Force of attraction between one atom and another within a compound formed by sharing of electrons or the loss and gain of electrons this is a bond

3 0

3 years ago

The slope of a linear position graph tells us the blank of the object

sveta [45]

Answer:

velocity of the object

Explanation:

For an object moving at a constant acceleration, we would expect to see a position graph with a curved shape and a velocity graph with a straight shape.

6 0

3 years ago

Two balls have masses 18 kg and 47 kg. The 18 kg ball has an initial velocity of 76 m/s (to the right) along a line joining the

BigorU [14]

Answer:

The final velocity of 18 kg ball is $V_{2}$ = 42.09 $\frac{m}{sec}$

Explanation:

Mass of first ball $m_{1}$ = 18 kg

Mass of second ball $m_{2}$ = 47 kg

Initial velocity of 18 kg ball $V_{1}$ = 76 $\frac{m}{sec}$

Initial velocity of 47 kg ball = 0

Final velocity of 18 kg ball $V_{2}$ = ??

Final velocity of 18 kg ball is given by the formula

$V_{2}$ = $\frac{2 m_{1} V_{1} }{m_{1} + m_{2} }$

Put all the values in above formula we get

$V_{2}$ = 2 × 18 × $\frac{76}{65}$

$V_{2}$ = 42.09 $\frac{m}{sec}$

Thus, the final velocity of 18 kg ball is $V_{2}$ = 42.09 $\frac{m}{sec}$

3 0

3 years ago

Derive the following equations of motion

xz_007 [3.2K]

Answer:

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<h3>a. Let us assume a body has initial velocity 'u' and it is subjected to a uniform acceleration 'a' so that the final velocity 'v' after a time interval 't'. Now, By the definition of acceleration, we have:</h3>

$a = \frac{v - u}{t} \\ or \: at = v - u \\ v = u + at \:$

It is first equation of motion.

___________________________________

<h3>b. Let us assume a body moving with an initial velocity 'u'. Let it's final body 'v' after a time interval 't' and the distance travelled by the body becomes 's' then we already have,</h3>

$v = u + at...........(i) \\ s = \frac{u + v}{2} \times t.........(ii)$

Putting the value of v from the equation (i) in equation (ii), we have,

$s= \frac{u + (u + at)}{2} \times t \: \: \\ or \: s = \frac{(2u + at)t}{2} \\ or \: s = \frac{2ut + a {t}^{2} }{2} \\ s = ut + \frac{1}{2} a {t}^{2}$

It is third equation of motion.

________________________________

<h3>c. Let us assume a body moving with an initial velocity 'u'. Let it's final velocity be 'v' after a time and the distance travelled by the body be 's'. We already have,</h3>

$v = u + at.....(i) \\ s = \frac{u + v}{2} \times t......(ii) \\$

$v = u + at \\ or \: at = v - u \\ t = \frac{v - u}{a}$

Putting the value of t from (i) in the equation (ii)

$s = \frac{u + v}{2} \times \frac{v - u}{a} \\ or \: s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ or \: 2as = {v}^{2} - {u}^{2} \\ {v}^{2} = {u}^{2} + 2as$

It is forth equation of motion.

________________________________

Hope this helps...

Good luck on your assignment..

3 0

3 years ago

Abox has a mass of 14.4 kg. The length is 4 m longthe width is 1 m and the height is 5 m. What is the density of the box?

valkas [14]

Answer:

0.72 kg per cubic m

Explanation:

Mass = 14.4 kg

Volume = lbh = 4*1*5 = 20 cubic m

$\because \: density \\ \\ = \frac{mass}{volume} \\ \\ = \frac{14.4}{20} \\ \\ = 0.72 \: kg {m}^{ - 3}$

3 0

3 years ago