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3 years ago

Which example provides the most complete description of an object's motion?

Physics

2 answers:

eduard3 years ago

7 0

Answer:

In this case in option 4:

The hiker followed a northbound road for 2 miles in 30 minutes.

Explanation:

Hello ! Let's solve this!

To know the description of a movement we have to know the distance it travels and the time it takes to travel it.

In this case in option 4:

The hiker followed a northbound road for 2 miles in 30 minutes.

Distance: 2 miles

time: 30min

Then we can calculate the speed of the hiker

cupoosta [38]3 years ago

5 0

Answer:

The hiker followed a road heading north for 2 miles in 30 minutes.

Explanation:

In order to describe the motion of an object, distance covered and time taken must be required. The total path covered by an object is called the distance travelled.

The hiker followed a road heading north for 2 miles in 30 minutes. This describes the motion of hiker. The motion shows how fast the hiker is moving.

Distance, d = 2 miles = 3218.6 m

times, t = 30 minutes = 1800 seconds

So, we can say that the hiker is moving with a speed of 1.78 m/s in north direction.

Hence, this is the required solution.

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A passenger on a stopped bus notices that rain is falling vertically just outside the window. When the bus moves with constant v

nekit [7.7K]

Answer:

1)0.325

2) $6.17\ \rm m/s$

Explanation:

<u>Given:</u>

The angle that falling raindrops make with the vertical= $18^\circ$

Let $V_R$ be the velocity of the raindrops and $V_B$ be the velocity of the bus.

$\dfrac{V_R}{V_B}=\tan 18^\circ\\\dfrac{V_R}{V_B}=0.315\\$

2)Speed of the raindrops $=0.315\times 19$

$=6.17\ \rm m/s$

5 0

2 years ago

What explains the information needed to calculate speed and velocity?

Ede4ka [16]

To calculate speed, you need to know the total distance covered
and the time it took to cover the distance.

To calculate velocity, you need the starting location, the ending location,
and the time it took to go from start to finish.

3 0

3 years ago

A 78.5-kg man is standing on a frictionless ice surface when he throws a 2.40-kg book horizontally at a speed of 11.3 m/s. With

kirill [66]

Answer:

The man moves across the ice with a speed of 0.345m/s.

Explanation:

From the conservation of linear momentum, we have that the total linear momentum before the book throw is equal to the total linear momentum just after it. Since the initial velocity of the system is zero (so the initial momentum is zero), we have that:

$m_mv_m+m_bv_b=0\\\\v_m=-\frac{m_b}{m_m} v_b$

Where $m_m$ is the mass of the man, $m_b$ is the mass of the book, and $v_m$ and $v_b$ are their velocities. Plugging in the given values, we can compute the speed of the man (ignoring the negative sign, because we care about the magnitude, not the direction):