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Mrrafil [7]
4 years ago
14

We need standard units to measure the physical quantity ​

Mathematics
1 answer:
Gekata [30.6K]4 years ago
7 0

Answer:

true

Step-by-step explanation:

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What is three and one third divided by two and one third
Mkey [24]
The correct answer is 10/7 or 1 3/7. Hope this helps.
3 0
3 years ago
Read 2 more answers
A marketing firm claims that its ad campaign will increase sales for a fast-food chain by 15%. In a random sample of 49 stores,
enyata [817]

Answer:

4.20

Step-by-step explanation:

Given data:

the average increase in sales 'x' = 18

ad campaign will increase sales for a fast-food chain 'μ'= 15

standard deviation 'σ'= 5

random sample of stores 'n'=49

In order to determine z-value, we use the formula i.e

z=( x-μ ) / (σ/\sqrt{n} )

z=( 18-15) / (5/\sqrt{49 )

z= 3/ 0.714

z= 4.20

4 0
4 years ago
Please help with hold page it is not alot I'm running out of the time
Travka [436]
I'll teach you how to do them, but not do them all for you.

2.
6:5 = ___:35
35 / 5 = 7
So you've got to multiply 6 by 7.
6:5 = 42:35

3. 
2:3 = 20:___
20 / 2 = 10
So you've got to multiply 3 by 10
2:3=20:30

4. 
36:24 = 6:___
36 / 6 = 6
So you've got to divide 24 by 6.
36:24 = 6:4

Keep trying and if you need more help feel free to ask.

7 0
4 years ago
Unconditioned stimulus​
fgiga [73]

Answer:

An unconditioned stimulus is a stimulus that leads to an automatic response.

3 0
3 years ago
Find four distinct complex numbers (which are neither purely imaginary nor purely real) such that each has an absolute value of
Luda [366]

Answer:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i

Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

  • |C| = \sqrt{a^2+b^2}

Then, the work consists in finding pairs (a,b) for which:

  • \sqrt{a^2+b^2}=3

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}

I will use b =0.5, b = 1, b = 1.5, b = 2

b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236

Then, four distinct complex numbers that have an absolute value of 3 are:

  • 0.5 + 2.985i
  • 1 + 2.828i
  • 1.5 + 2.598i
  • 2 + 2.236i
4 0
4 years ago
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