the mass of aluminum oxide (101.96 g/mol) produced from 1.74 g of manganese(iv) oxide (86.94 g/mol) is 1.36g
The reaction is 3 MnO2 + 4 Al ------ 2Al2o3+ Mn
3 mole of manganese oxide give 2 moles of aluminum oxide so by the reaction n( MnO2)/3 =n(al203)2
the formula is n= mass/M so, now substituting values
m (Al2O3)= m(MnO2) X 2 X M (Al2O3) / M(MnO2 X3
so, by substituting values, 2 X101.96 X1.74g / 3 X 86.94 =1.36g
so mass of aluminum oxide obtained = 1.36g
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False, because generally forensics collect the evidence to make sure the evidence doesn’t get damaged or tainted.... hope this helps
Answer:
Ca(OH)₂ and HCl(aq)
Explanation:
We have the products of a reaction, CaCl₂ and H₂O. Since the products are a salt and water, this is likely to be a neutralization reaction. In such a reaction, an acid and a base react to form a salt and water.
- The acid provides the anion of the salt. Since the anion is Cl⁻, the acid is HCl(aq).
- The base provides the cation of the salt. Since the cation is Ca²⁺, the base is Ca(OH)₂(aq).
The complete molecular equation is:
Ca(OH)₂ + 2 HCl(aq) → CaCl₂ + 2 H₂O
sedimentary. almost all fossils are found in sedimentary rocks
<span>Chemical change is any change that results in the formation of new chemical substances. </span>
