A graduated cylinder has 100 mL of water in it. A rock is then placed in the cylinder

How many liters of nitrogen gas is produced if 50.0L of water is produced at STP?

Alona [7]

Answer:

25.0 liter of nitrogen gas

Explanation:

1. Chemical equation

Ammonium nitrite is a solid compound that decomposes into nitrogen gas and water vapor as per this chemical equation:

$NH_4NO_2(s)\rightarrow N_2(g)+2H_2O(g)$

2. Mole ratio

$1molN_2(g)/2molH_2O(g)$

3. Volume ratio

Since, both species are gases and are at same temperature and pressure, the volume ratio is equal to the mol ratio.

Thus, the volume ratio is:

$1literN_2(g)/2literH_2O(g)$

4. Use the volume ratio with the known amount of water produced

$50.0literH_2O(g)\times 1literN_2(g)/2literH_2O(g)=25.0literN_2(g)$

8 0

2 years ago

HELPPPPPP 30 POINTS Scientists are currently debating if a new epoch based on modern human activity should be added to the geolo

Margarita [4]

Answer:

Anthropocene

Explanation:

Anthropocene epoch is sort of unofficial epoch that scientists have used to describe basically human made impact on geological scale.

here's more info:

https://www.earthsystems.com/the-anthropocene/

3 0

1 year ago

W(OH)2 + 2 HCl → WCl2 + 2 H2O

Afina-wow [57]

The amount of W(OH)2 needed would be 448.126 g

<h3>Stoichiometric calculation</h3>

From the equation of the reaction:

W(OH)2 + 2 HCl → WCl2 + 2 H2O

The mole ratio of W(OH)2 to HCl is 1:2

Mole of 150g HCl = 150/36.461

= 4.11 moles

Equivalent mole of W(OH)2 = 4.11/2

= 2.06 moles

Mass of 2.06 moles W(OH)2 = 2.06 x 217.855

= 448.188g

More on stoichiometric calculations can be found here: brainly.com/question/8062886

7 0

1 year ago

What observations can you make about this group of people? Name one inference you can make from your observations.

Vlad1618 [11]

Answer:

What group of people ay?

Maybe look at their differences in appearance: height, size, weight, skin color, clothing choice?

7 0

2 years ago

Read 2 more answers

The conversion of cyclopropane to propene occurs with a first-order rate constant of . How long will it take for the concentrati

Gennadij [26K]

This is an incomplete question, here is a complete question.

The conversion of cyclopropane to propene occurs with a first-order rate constant of 2.42 × 10⁻² hr⁻¹. How long will it take for the concentration of cyclopropane to decrease from an initial concentration 0.080 mol/L to 0.053 mol/L?

Answer : The time taken will be, 17.0 hr

Explanation :

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = $2.42\times 10^{-2}\text{ hr}^{-1}$

t = time passed by the sample = ?

a = initial concentration of the reactant = 0.080 M

a - x = concentration left = 0.053 M

Now put all the given values in above equation, we get

$t=\frac{2.303}{2.42\times 10^{-2}}\log\frac{0.080}{0.053}$

$t=17.0\text{ hr}$

Therefore, the time taken will be, 17.0 hr

5 0

2 years ago