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artcher [175]
4 years ago
6

The bond between F and Cl would be: pure covalent polar covalent ionic metallic

Chemistry
1 answer:
shusha [124]4 years ago
3 0

Answer:

Polar Covalent

Explanation:

Chlorine and Fluorine are both halogens. They are in group VII.

The Pauling's electronegativity value of these elements are:

F = 4.0

Cl = 3.0

Electronegativity of an element is a property that combines the ability of its atom to lose and gain electrons. It can be used to predict bond type.

For heteronuclear molecules where the electronegativity difference is between 0.5 and 1.7 there will not be an equal sharing of the electron pair between the atoms involved.

The bond that results is a Polar Covalent bond.

When the electronegativity difference is zero or less than 0.5, a non-polar covalent bond forms. There would be an equal sharing of the electron pair donated.

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Explanation:

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4 years ago
How many moles of water would form the reaction of exactly 58.3 grams of magnesium hydroxide
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Answer:

\boxed{\text{2.00 mol}}

Explanation:

We know we will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

You don't tell us what the reaction is, but we can solve the problem so long as we balance the OH.

M_r:      58.32

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(a) Moles of Mg(OH)₂

\text{Moles of Mg(OH)$_{2}$} =\text{58.3 g Mg(OH)$_{2}$} \times \dfrac{\text{1 mol Mg(OH)$_{2}$}}{\text{58.32 g Mg(OH)$_{2}$}}\\\\=\text{0.9997 mol Mg(OH)$_{2}$}

(b) Moles of H₂O

The molar ratio is 2 mol H₂O = 1 mol Mg(OH)₂.

\text{Moles of H$_{2}$O}= \text{0.9995 mol Mg(OH)$_{2}$} \times \dfrac{\text{2 mol {H$_{2}$O}}}{ \text{1 mol Mg(OH)$_{2}$}}\\\\= \textbf{2.00 mol H$_{2}$O}

The reaction will form \boxed{\textbf{2.00 mol}} of water.

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