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NeX [460]
3 years ago
14

Zinc metal is produced by heating solid zinc sulfide with solid wine witte resulting in liquid zinc and sulfur dioxide gas Write

a balanced equation for the reaction using complete formulas for the compounds with phase labels (Use the lowest possible coefficients. Use the pull down boxes to specify states such as (aq) or (b). If a box is not needed, leave it blank.) Submit Answer Try Another Version item attempts remaining
Chemistry
1 answer:
elena-s [515]3 years ago
4 0

Answer:

The balance chemical equation can be given as:

ZnS(s)+ZnSO_4(aq)\overset{heat}\rightarrow 2Zn(s)+2SO_2(g)

Explanation:

When zinc sulfide is allowed to react with zinc sulfate it gives zinc metal and sulfur dioxide gas as a product.The balance chemical equation can be given as:

ZnS(s)+ZnSO_4(aq)\overset{heat}\rightarrow 2Zn(s)+2SO_2(g)

According to reaction we can see when 1 mol of zinc sulfide reacts with 1 mol of zinc sulfate it forms 2 moles of zinc metal and 2 moles of sulfur dioxide gas.

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Give the half equation to show what happens to oxygen when it is rusting
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½O 2 + 2e - + H 2O → 2OH.

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3 0
3 years ago
Calculate the percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl on the assumption that t
stealth61 [152]

Answer:

1.089%

Explanation:

From;

ν =1/2πc(k/meff)^1/2

Where;

ν = wave number

meff = reduced mass or effective mass

k = force constant

c= speed of light

Let

ν =1/2πc (k/meff)^1/2  vibrational wave number for 23Na35 Cl

ν' =1/2πc(k'/m'eff)^1/2 vibrational wave number for 23Na37 Cl

The between the two is obtained from;

ν' - ν /ν  = (k'/m'eff)^1/2 - (k/meff)^1/2 / (k/meff)^1/2

Therefore;

ν' - ν /ν = [meff/m'eff]^1/2 - 1

Substituting values, we have;

ν' - ν /ν = [(22.9898 * 34.9688/22.9898 + 34.9688) * (22.9898 + 36.9651/22.9898 * 36.9651)]^1/2  -1

ν' - ν /ν = -0.01089

percentage difference in the fundamental vibrational wavenumbers of 23Na35Cl and 23Na37Cl;

ν' - ν /ν * 100

|(-0.01089)|  × 100 = 1.089%

4 0
3 years ago
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