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jenyasd209 [6]
3 years ago
14

How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?

Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Answer:- 55 g of LiCl are required to make 2.0 L of 0.65 M solution.

Solution:- Given-

molarity of the solution = 0.65M

Volume of solution = 2.0 L

molarity of solution = \frac{moles of solute}{volume of solution in liter}

It could be arranged as...

moles of solute = molarity x volume of solution

moles of solute = 0.65 x 2.0 = 1.3 moles

Molar mass of LiCl is 42.39 g/mol.

So, mass of LiCl required = 1.3 mol x 42.39g/mol = 55 g

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<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

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Reaction

Zn + HNO₃⇒ Zn(NO₃)₂ + NO + H₂O

  • 1. gives a coefficient

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  • 2. make an equation

Zn : left = a, right =1 ⇒a=1

H : left = b, right = 2d⇒ b=2d (eq 1)

N : left = b, right = 2+c⇒b=2+c (eq 2)

O : left = 3b, right = 6+c+d ⇒3b=6+c+d(eq 3)

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c = 2/3

  • input eq 5

d = 2 x 2/3

d = 4/3

  • input eq 1

b = 2 x 4/3

b = 8/3

The equation

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