Question

How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?

Answer 1

Answer:- 55 g of LiCl are required to make 2.0 L of 0.65 M solution.

Solution:- Given-

molarity of the solution = 0.65M

Volume of solution = 2.0 L

molarity of solution = $\frac{moles of solute}{volume of solution in liter}$

It could be arranged as...

moles of solute = molarity x volume of solution

moles of solute = 0.65 x 2.0 = 1.3 moles

Molar mass of LiCl is 42.39 g/mol.

So, mass of LiCl required = 1.3 mol x 42.39g/mol = 55 g