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jenyasd209 [6]
3 years ago
14

How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?

Chemistry
1 answer:
makkiz [27]3 years ago
4 0

Answer:- 55 g of LiCl are required to make 2.0 L of 0.65 M solution.

Solution:- Given-

molarity of the solution = 0.65M

Volume of solution = 2.0 L

molarity of solution = \frac{moles of solute}{volume of solution in liter}

It could be arranged as...

moles of solute = molarity x volume of solution

moles of solute = 0.65 x 2.0 = 1.3 moles

Molar mass of LiCl is 42.39 g/mol.

So, mass of LiCl required = 1.3 mol x 42.39g/mol = 55 g

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Answer:

The glycosylation reaction or glycoside formation is an organic reaction in which the hemiacetal group of cyclists ketoses or aldoses turns into acetals, named glycosides. Reaction in the attached picture.

Explanation:

Carbohydrates can be found in an open-chain form or a cyclic form. For the second one, the carbonyl group of the aldehyde could react with the alcohol group of the molecule to form the cycle. As shown in the attached picture, the alcohol group of this cyclic form could react with an alcohol (like methanol) in acidic conditions to form an acetal. These compounds are stable at neutral and acidic conditions, but they hydrolyze at basic conditions. This reaction produces both acetals anomers (α and β) because the attack of the nucleophile (alcohol) could be from both sides. However, the most stable anomer will predominate.

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3 years ago
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Answer:

5.004kg

Explanation:

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volume of CO2 produced=1000×22.4/12

volume of CO2 produced =1866.6dm3

from the combustion reaction equation provided

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applying the same relationship of molar ratio

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therefore

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from the first calculation

vol of CO2=1866.6dm3

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mass of urea=5004.82kg

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Explanation:

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Answer:

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