How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?
1 answer:
Answer:- 55 g of LiCl are required to make 2.0 L of 0.65 M solution.
Solution:- Given-
molarity of the solution = 0.65M
Volume of solution = 2.0 L
molarity of solution =
It could be arranged as...
moles of solute = molarity x volume of solution
moles of solute = 0.65 x 2.0 = 1.3 moles
Molar mass of LiCl is 42.39 g/mol.
So, mass of LiCl required = 1.3 mol x 42.39g/mol = 55 g
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Answer:
A beaker
Step-by-step explanation:
Specifically, I would use a 250 mL graduated beaker.
A beaker is appropriate to measure 100 mL of stock solution, because it's easy to pour into itscwide mouth from a large stock bottle.
You don't need precisely 100 mL solution.
If the beaker is graduated, you can easily measure 100 mL of the stock solution.
Even if it isn't graduated, 100 mL is just under half the volume of the beaker, and that should be good enough for your purposes (you will be using more precise measuring tools during the experiment).
