How many grams of LiCl are required to make 2.0 L of 0.65 M LiCl solution?
1 answer:
Answer:- 55 g of LiCl are required to make 2.0 L of 0.65 M solution.
Solution:- Given-
molarity of the solution = 0.65M
Volume of solution = 2.0 L
molarity of solution =
It could be arranged as...
moles of solute = molarity x volume of solution
moles of solute = 0.65 x 2.0 = 1.3 moles
Molar mass of LiCl is 42.39 g/mol.
So, mass of LiCl required = 1.3 mol x 42.39g/mol = 55 g
You might be interested in
a) When the reaction takes place a yellow precipitate will be formed.
b) The law of conservation of mass is true.
<u>Explanation:</u>
a) When a lead nitrate solution is mixed with a potassium chromate solution, a yellow precipitate containing lead forms according to the equation:
→
b) Law of conservation of mass for the given reaction is true.
From the given table we know the mass of reactants and its products.
Law of conservation of mass is a principle when a reaction takes place in a closed system, the mass of the products and reactants in the system doesn't change.
⇒The sum of the mass of the reactants = The sum of the mass of the products.
The sum of the reactants = 128.71+128.97.
= 257.68 g.
The sum of the products = 154.10+103.58.
= 257.68 g.
Thus law of conservation of mass is true for the above reaction.