Try this solution:
1. the standart form of the circle is: (x-x₀)²+(y-y₀)²=r², where point (x₀;y₀) - the cetre of the given circle, r - radius of the given circle.
2. Using r=7 and coordinates of the centre (0;0) it is possible to make up the required equation:
(x-0)²+(y-0)²=7²;
x²+y²=49.
Yonna, this is the solution to the problem:
Side 1 of the tablet = (4x + 3) cm
Side 2 of the tablet = (-4x² - 2x - 3) cm
Area of the tablet = Side 1 * Side 2
Area of the tablet = (4x + 3) * (-4x² - 2x - 3) cm²
Area of the tablet = (4x * -4x²) + (4x * -2x) + (4x * -3) + (3 * -4x²) + (3 * -2x) + (3 * -3)
Area of the tablet = -16x³ - 8x² - 12x - 12x² - 6x - 9 cm²
Area of the tablet = -16x³ - 20x² - 18x - 9 cm²
<h3>Given</h3>
<h3>Find</h3>
<h3>Solution</h3>
It can be convenient to rewrite f(x) as a square, then do the substitution. That way, the algebra is simplified a little bit.
... f(x) = (x +1)²
... f((2a-3)/5) = ((2a-3)/5 +1)² = ((2a -3 +5)/5)²
... = (2/5(a+1))²
... f((2a-3)/5) = (4/25)(a² +2a +1)
Answer:
a = 3, b = 5
Step-by-step explanation:
Given
x² - 6x + 4 = 0 ( subtract 4 from both sides )
x² - 6x = - 4
Using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(- 3)x + 9 = - 4 + 9
(x - 3)² = 5 ( take the square root of both sides )
x - 3 = ± 
( add 3 to both sides )
x = 3 ± ← in the form a ± 
with a = 3 and b = 5
