Answer : The oxidation state of nitrogen in 
is, (+5)
Explanation :
Rules for the oxidation numbers :
- The oxidation number of a free element is always be zero.
- The oxidation number of a monatomic ion equal to the charge of the ion.
- The oxidation number of Hydrogen (H) is +1.
- The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in the peroxides.
- The oxidation number of a Group 1 element in a compound is +1.
- The oxidation number of a Group 2 element in a compound is +2.
- The oxidation number of a Group 17 element in a binary compound is -1.
- The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
- The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given compound is,
Let the oxidation state of 'N' be, 'x'
Hence, the oxidation state of N is, (+5)
The red semicircle shown in the weather chart represents warm front.
From the calculations and by the use of Boyles law, the new pressure of the gas is 1.7 atm
<h3>What are gas laws?</h3>
The term gas law is used to demonstrate the relationship between the volume, pressure, number of moles and temperature of a gas.
Using the Boyles law;
P1 = 1 atm
P2 = ?
V1 = 6 L
V2 = 3.5 L
P1V1= P2V2
P2= P1V1/V2
P2= 1 atm * 6 L/3.5 L
= 1.7 atm
Learn more about Boyles law:brainly.com/question/1437490
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<u>Answer:</u> From the given gases, the greatest rate of effusion is of 
<u>Explanation:</u>
Rate of effusion of a gas is determined by a law known as Graham's Law.
This law states that the rate of effusion or diffusion of a gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:
It is visible that molar mass is inversely related to rate of effusion. So, the gas having lowest molar mass will have the highest rate of effusion.
For the given gases:
Molar mass of 
Molar mass of 
Molar mass of 
Molar mass of 
Molar mass of 
The molar mass of methane gas is the lowest. Thus, it will have the greatest rate of effusion.
Hence, the greatest rate of effusion is of
This equation is balanced
