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3 years ago

How are ocean waves different from sound waves?

Chemistry

2 answers:

Luba_88 [7]3 years ago

5 0

Answer:

Ocean waves are longitudinal waves, Sound waves are transverse waves. Ocean waves are electromagnetic waves, Sound waves are mechanical waves. A Sound wave of over 20,000 Cycles per Seconds is inaudible to Humans.

Explanation:

larisa [96]3 years ago

4 0

Answer:

Ocean waves are mechanical waves while Sound waves are electromagnetic waves

Explanation:

You might be interested in

How many moles are in 5.6x1025 molecules of calcium oxide?

Vlad1618 [11]

Answer:

<h2>93.02 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...$

We have the final answer as

<h3>93.02 moles</h3>

Hope this helps you

8 0

3 years ago

Look up the active ingredient in baking soda. Write a molecular and net ionic equation when that active ingredient is mixed with

Volgvan

Answer:

The active ingredients in baking soda (NaHCO3) are

$Na^+$ and $HCO3^-$

when Baking soda reacts with Acetic acid

Molecular equation

NaHCO3(aq) + CH3COOH(aq) → Na(CH3COO)(aq) + CO2(g) +H2O(l)

Ionic equation

$Na^+ + HCO3^- + CH3COOH$ → $Na^+ + CH3COO^- +CO2 + H2O$

as $Na^+$ is present on both sides so it will cancel out and the net ionic equation will be

$HCO3^-(aq) + CH3COOH(aq)$ → $CH3COO^-(aq) + CO2(g) + H2O(l)$

6 0

3 years ago

Consider the insoluble compound nickel(II) hydroxide , Ni(OH)2 . The nickel ion also forms a complex with cyanide ions . Write a

natali 33 [55]

Answer: Equilibrium constant for this reaction is $2.8 \times 10^{15}$ .

Explanation:

Chemical reaction equation for the formation of nickel cyanide complex is as follows.

$Ni(OH)_{2}(s) + 4CN^{-}(aq) \rightleftharpoons [Ni(CN)_{4}^{2-}](aq) + 2OH^{-}(aq)$

We know that,

K = $K_{f} \times K_{sp}$

We are given that, $K_{f} = 1.0 \times 10^{31}$

and, $K_{sp} = 2.8 \times 10^{-16}$

Hence, we will calculate the value of K as follows.

K = $K_{f} \times K_{sp}$

K = $(1.0 \times 10^{31}) \times (2.8 \times 10^{-16})$

= $2.8 \times 10^{15}$

Thus, we can conclude that equilibrium constant for this reaction is $2.8 \times 10^{15}$ .

4 0

3 years ago

A standard solution is prepared for the analysis of fluoxymesterone (c20h29fo3; 336 g/mol), an anabolic steroid. a stock solutio

-Dominant- [34]

<em>Answer:</em>

The concentration of new solution will be 1×10∧-7 M.

<em>Solution:</em>

<em>Data Given </em>

given mass of fluoxymesterone =16.8mg = 0.0168 g

molar mass of fluoxymesterone = 336g/mol

vol. of fluoxymesterone = 500.0 ml = 0.500 L

Stock Molarity of fluoxymesterone = (0.0168/336)÷0.500 = 1×10∧-4 M

So applying dilution formula

Stock Solution : New Solution

M1.V1 = M2.V2

( 1×10∧-4 M) × (1×10∧-6 L) = M2 × 0.001 L

[( 1×10∧-4) × (1×10∧-6)]÷[0.001] = M2

1 × 10∧-7 = M2

<em>Result:</em>

The concentration of new solution M2 will be 1 × 10∧-7

3 0

3 years ago

What is the mass in grams of 3.0x10^23 molecules of carbon dioxide??

Sonja [21]

Moles of CO2 = number of molecules / 6.02x10^23. = 3x10^23/6.02x10^23 = 0.5moles. Therefore, mass of CO2 = moles x molecular mass of CO2= 0.5x44 = 22gm.

4 0

3 years ago